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2 years ago

In which type of chemical reaction do two or more substances combine to form one substance?

Chemistry

2 answers:

Stella [2.4K]2 years ago

7 0

A) synthesis reaction

sveticcg [70]2 years ago

6 0

Your answer should be a

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If calcium carbonate (CaCO3) decomposes, what would the product of the reaction be?

NemiM [27]

It was C) CaO on edg

8 0

2 years ago

Read 2 more answers

Calculate the density of CO2 in g/cm3 at room temperature(25 degrees Celsuis) and pressure(1 atm) assuming it acts as an ideal g

Readme [11.4K]

Answer:

$density=1.8x10^{-3}g/mL$

Explanation:

Hello,

Considering the ideal equation of state:

$PV=nRT$

The moles are defined in terms of mass as follows:

$n=\frac{m}{M}$

Whereas $M$ the gas' molar mass, thus:

$PV=\frac{mRT}{M}$

Now, since the density is defined as the quotient between the mass and the volume, we get:

$P=\frac{m}{V} \frac{RT}{M}$

Solving for $m/V$ :

$density= m/V=\frac{PM}{RT}$

Thus, the result is given by:

$density=\frac{(1atm)(44g/mol)}{[0.082atm*L/(mol*K)]*298.15K} \\density=1.8g/L=1.8x10^{-3}g/mL$

Best regards.

8 0

2 years ago

What is the percentage composition when 10g of magnesium combines with 4g of nitrogen?

Ivanshal [37]

The % composition when 10g of magnesium combine with 4g of nitrogen is 71.43% magnesium and 28.57 % nitrogen

calculation

% composition = mass of an element / total mass x100
mass of magnesium = 10 g
mass of nitrogen = 4g

calculate the total mass used

= 10g of Magnesium + 4 g of nitrogen = 14 grams

% composition for magnesium is therefore = 10/14 x100 = 71.43 %

% composition for nitrogen is therefore = 4 /14 x100 = 28.57 %

7 0

2 years ago

Place each statement in the column of the particle that it best describes.<br> Refer To Photo

MrRa [10]

The options are labelled as:

1 2

3 4

5 6

7 8

Protons: 1, 5, 7

Neutrons: 2, 8

Electron: 3, 4, 6

5 0

2 years ago

What is Δn for the following equation in relating Kc to Kp?2 SO2(g) + O2(g) ↔ 2 SO3(g)23-2-11

san4es73 [151]

Answer:

-1

Explanation:

The relation between Kp and Kc is given below:

$K_p= K_c\times (RT)^{\Delta n}$

Where,

Kp is the pressure equilibrium constant

Kc is the molar equilibrium constant

R is gas constant

T is the temperature in Kelvins

Δn = (No. of moles of gaseous products)-(No. of moles of gaseous reactants)

For the first equilibrium reaction:

$2SO_2_{(g)}+O_2_{(g)}\rightleftharpoons2SO_3_{(g)}$

Thus, Kp is:

$K_p= K_c\times (RT)^{-1}$

4 0

2 years ago