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3 years ago

Question: complete the mechanism for the below oxidation of an alkene with kmno4. draw the missing curved

Chemistry

1 answer:

iren2701 [21]3 years ago

6 0

Mechanism for oxidation of alkene by KMnO₄ is provided in the attached image:

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What is the name of an acid with the formula HNO2?

Step2247 [10]

HNO2 is the formula for Nitrous Acid

8 0

3 years ago

Given the following information, what is the concentration of H2O(g) at equilibrium? [H2S](eq) = 0.671 M [O2](eq) = 0.587 M Kc =

MAVERICK [17]

Answer: The equilibrium concentration of water is 0.597 M

Explanation:

Equilibrium constant in terms of concentration is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as $K_{c}$

For a general chemical reaction:

$aA+bB\rightleftharpoons cC+dD$

The expression for $K_{eq}$ is written as:

$K_{c}=\frac{[C]^c[D]^d}{[A]^a[B]^b}$

The concentration of pure solids and pure liquids are taken as 1 in the expression.

For the given chemical reaction:

$2H_2S(g)+O_2(g)\rightleftharpoons 2S(s)+2H_2O(g)$

The expression of $K_c$ for above equation is:

$K_c=\frac{[H_2O]^2}{[H_2S]^2\times [O_2]}$

We are given:

$[H_2S]_{eq}=0.671M$

$[O_2]_{eq}=0.587M$

$K_c=1.35$

Putting values in above expression, we get:

$1.35=\frac{[H_2O]^2}{(0.671)^2\times 0.587}$

$[H_2O]=\sqrt{(1.35\times 0.671\times 0.671\times 0.587)}=0.597M$

Hence, the equilibrium concentration of water is 0.597 M

8 0

3 years ago

Suppose you were preparing 1.0 L of a bleaching solution in a volumetric flask, and it calls for 0.21 mol of NaOCl. If all you h

yulyashka [42]

Answer:

0.256 L

Explanation:

We should use the following formula:

concentration (1) × volume (1) = concentration (2) × volume (2)

concentration (1) = 0.82 M NaOCl

volume (1) = ?

concentration (2) = 0.21 M NaOCl

volume (2) = 1 L

volume (1) = [concentration (2) × volume (2)] / concentration (1)

volume (1) = [0.21 / 1] / 0.82 = 0.256 L

3 0

3 years ago

Read 2 more answers

Sand dunes are created when the wind carrying the sand runs into an obstacle A. True B. False

Troyanec [42]

A. True

They are formed behind an obstacle when the wind blows the sand up to it.

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3 years ago

If the hydrogen ion concentration is 10-7M, what is the pH of the solution? Show all work.

Kobotan [32]

Remember pH=-log(H ions). So it would be pH=-log(10^-7).

6 0

3 years ago