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mrs_skeptik [129]
2 years ago
8

Covalent compounds are generally not very hard. Justify the statement.

Chemistry
1 answer:
Eduardwww [97]2 years ago
4 0

Covalent compounds are generally not very hard because they are formed by two or more nonmetallic atoms.

<h3>COVALENT COMPOUNDS:</h3>

Covalent compounds are compounds whose constituent elements are joined together by covalent bonds.

Covalent bonding occurs when two or more nonmetallic atoms of an element share valence electrons. This means that covalent compounds will not be physically hard since they constitute non-metals.

Examples of covalent compounds are:

  1. H2 - hydrogen
  2. H2O - water
  3. HCl - hydrogen chloride
  4. CH4 - methane

Learn more about covalent compounds at: brainly.com/question/21505413

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WARRIOR [948]

Answer:

no

Explanation:

4 0
2 years ago
When placed in a 100mL cube shaped box a substance fills the cube and has a volume of 100 mL. When places in a 50mL tube that sa
Whitepunk [10]

There are five states of matter out of which we encounter three states of matter in our day today life

a) gas b) solid and c) liquid

the main difference between the three is of

a) Inter molecular forces of attraction

b) thermal energy

due to this

a) solid has high intermolecular forces and low thermal energy: thus they have fix shape and occupy fix volume

b) liquid has intermediate forces and medium themal energy. Thus they may have fixed volume and but no fix shape

c) gas has weak intermoelcular forces and high thermal energy. thus they have no fixed volume no fix shape

so in the given problem

the state of the substance D- Gas.

8 0
3 years ago
The combustion of 0.570 g of benzoic acid (ΔHcomb = 3,228 kJ/mol; MW = 122.12 g/mol) in a bomb calorimeter increased the tempera
torisob [31]

Answer:

The temperature change from the combustion of the glucose is 6.097°C.

Explanation:

Benzoic acid;

Enthaply of combustion of benzoic acid = 3,228 kJ/mol

Mass of benzoic acid = 0.570 g

Moles of benzoic acid = \frac{0.570 g}{122.12 g/mol}=0.004667 mol

Energy released by 0.004667 moles of benzoic acid on combustion:

Q=3,228 kJ/mol \times 0.004667 mol=15.0668 kJ=15,066.8 J

Heat capacity of the calorimeter = C

Change in temperature of the calorimeter = ΔT = 2.053°C

Q=C\times \Delta T

15,066.8 J=C\times 2.053^oC

C=7,338.92 J/^oC

Glucose:

Enthaply of combustion of glucose= 2,780 kJ/mol.

Mass of glucose=2.900 g

Moles of glucose = \frac{2.900 g}{180.16 g/mol}=0.016097 mol

Energy released by the 0.016097 moles of calorimeter  combustion:

Q'=2,780 kJ/mol \times 0.016097 mol=44.7491 kJ=44,749.1 J

Heat capacity of the calorimeter = C (calculated above)

Change in temperature of the calorimeter on combustion of glucose = ΔT'

Q'=C\times \Delta T'

44,749.1 J=7,338.92 J/^oC\times \Delta T'

\Delta T'=6.097^oC

The temperature change from the combustion of the glucose is 6.097°C.

6 0
2 years ago
(6.02×10^23)(8.65×10^4)
Katen [24]
I believe the answer to this is 5.2073*10^28
4 0
3 years ago
Consider these compounds:
Gnom [1K]

Explanation:

If we compare its solubility products without any calculation then, Magnesium hydroxide is more soluble than compound A and C. Magnesium hydroxide is less soluble than compound D.

- The solubility product of magnesium hydroxide and zinc carbonate is same so it is not possible to determine whether it is more or less soluble than compound B

6 0
3 years ago
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