CAN SOMEONE THATS GOOD AT CHEM PLEASE HELP ME?!?!

Snezhnost [94]

Actually, that does not happen until the protostar becomes a star when nuclear ignition starts and is maintained. It takes awhile for new star to go through its T-Tauri stage and settle down on the main sequence.

<span>A STAR does not reach hydrostatic equilibrium until it on the main sequence. Otherwise, it would remain a brown dwarf with not enough mass to to maintain nuclear fusion for more than 3,000 to 10,00 years. </span>

5 0

3 years ago

Read 2 more answers

g A radioactive isotope of mercury, 197Hg, decays to gold, 197Au, with a disintegration constant of 0.0108hrs.-1. What % of the

weqwewe [10]

Answer:

7.49% of Mercury

Explanation:

Let N₀ represent the original amount.

Let N represent the amount after 10 days.

From the question given above, the following data were obtained:

Rate of disintegration (K) = 0.0108 h¯¹

Time (t) = 10 days

Percentage of Mercury remaining =?

Next, we shall convert 10 days to hours. This can be obtained as follow:

1 day = 24 h

Therefore,

10 days = 10 day × 24 h / 1 day

10 days = 240 h

Thus, 10 days is equivalent to 240 h.

Finally, we shall determine the percentage of Mercury remaining as follow:

Rate of disintegration (K) = 0.0108 h¯¹

Time (t) = 10 days

Percentage of Mercury remaining =?

Log (N₀/N) = kt /2.303

Log (N₀/N) = 0.0108 × 240 /2.303

Log (N₀/N) = 2.592 / 2.303

Log (N₀/N) = 1.1255

Take the anti log of 1.1255

N₀/N = anti log 1.1255

N₀/N = 13.3506

Invert the above expression

N/N₀ = 1/13.3506

N/N₀ = 0.0749

Multiply by 100 to express in percent.

N/N₀ = 0.0749 × 100

N/N₀ = 7.49%

Thus, 7.49% of Mercury will be remaining after 10 days

5 0

2 years ago

A 10,0-L cylinder of gas is stored at room temperature (20.0°C) and a pressure of 1800 psi. If the gas is

makvit [3.9K]

Considering the Charles' law, the gas would have a temperature of -109.2 C.

<h3>Charles' law</h3>

Finally, Charles' law establishes the relationship between the volume and temperature of a gas sample at constant pressure. This law says that the volume is directly proportional to the temperature of the gas. That is, if the temperature increases, the volume of the gas increases, while if the temperature of the gas decreases, the volume decreases.

Charles' law is expressed mathematically as:

$\frac{V}{T} =k$

If you want to study two different states, an initial state 1 and a final state 2, the following is true:

$\frac{V1}{T1} =\frac{V2}{T2}$

<h3>Temperature of the gas in this case</h3>

In this case, you know:

P1= 1800 psi
V1= 10 L
T1= 20 C= 293 K (being 0 C= 273 K)
P2= 1800 psi
V2= 6 L
T2= ?

You can see that the pressure remains constant, so you can apply Charles's law.

Replacing in the Charles's law:

$\frac{10 L}{293 K} =\frac{6 L}{T2}$

Solving:

$\frac{10 L}{293 K} T2=6 L$

$T2=\frac{6 L}{\frac{10 L}{293 K} }$

The gas would have a temperature of -109.2 C.

Learn more about Charles's law:

brainly.com/question/4147359?referrer=searchResults

7 0

2 years ago

Calculate the heat change involved when 2.00 L of water is heated from 20.0/C to 99.7/C in

Pani-rosa [81]

Answer:

666,480 Joules or 669.48 kJ

Explanation:

We are given;

Volume of water as 2.0L or 2000 ml

but, density of water is 1 g/ml

Therefore, mass of water is 2000 g

Initial temperature as 20 °C
Final temperature as 99.7° C

Required to determine the heat change

We know that ;

Heat change = Mass × Temperature change × specific heat

In this case;

Specific heat of water is 4.2 J/g°C

Temperature change is 79.7 °C

Therefore;

Heat change = 2000 g × 79.7 °C × 4.2 J/g°C

= 669,480 Joules 0r 669.48 kJ

Thus, the heat change involved is 666,480 Joules or 669.48 kJ

5 0

3 years ago

Given the following balanced reaction: 2 NH3 +CO2 --> CH4N2O + H2O A reaction produces 87.5g of CH4N2O upon the reaction of 6

tankabanditka [31]

Answer:

ml lang yan pre tara laro

5 0

3 years ago