Chemical is the answer to the question, but nuclear could also be a valid one since it is nearly impossible to reverse that.
Answer:
H2SO3 + 2CsOH —> Cs2SO3 + 2H2O
Explanation:
When sulfurous acid react with caesium hydroxide, caesium sulfite and water are formed according to the equation:
H2SO3 + CsOH —> Cs2SO3 + H2O
Next, we balanced the equation by putting 2 in front of CsOH and 2 in front of H2O i.e
H2SO3 + 2CsOH —> Cs2SO3 + 2H2O
The reaction involved in present case is:
Net Reaction: Ca + 1/2 O2 → CaO. ..................(1)
In terms of oxidation and reduction, the reaction can be shown at
Oxidation: Ca → Ca2+ + 2e- .................(2)
Reduction: 1/2O2 + 2e- → O2-...................(3)
From, reaction 1 it can be seen that 1 mol of Ca reacts with 1/2 mol of O2 to form 1 mol of CaO.
From, reaction 2 it can be seen that 1 mol of Ca, generates 2 mol of e-.
Thus, when 1/2 mol of Ca is used in reaction, it will lose 1 mol of electrons.
Answer:
Jose and Sarah are running in the cross country meet. Their skeletal and muscular systems work to move them through the course. As they run, they breathe faster and harder and their heart rate increases.
A.work together
Explanation:This should help:)
Answer: 0.18 M
Explanation:
Initial molarity, M1 = 0.8 M
Initial olume, V1 = 225 ml
Final volume, V2 = 1000 ml
Final Molarity, M2 = M1V1/V2
= 0.8 x 225/1000
= 0.18 M