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GaryK [48]
3 years ago
11

You are buying boxes of cookies at a bakery. Each box of cookies costs 4 dollars. In the equation below, c represents the number

of boxes of cookies you buy, and d represents the amount the cookies will cost you (in dollars).
The relationship between these two variables can be expressed by the following equation:
d=4c
Mathematics
1 answer:
Yuliya22 [10]3 years ago
7 0
What the answer you want to find out ?
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Lin took 75 boxes of carrots and 80 boxes of potatoes to the market. She sold 68 boxes of carrots and 71 boxes of potatoes. How
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She took 7 boxes of carrots and 9 boxes of potatoes home.

75 boxes of carrots - 68 boxes of carrots = 7 boxes of carrots.

80 boxes of potatoes - 71 boxes of potatoes = 9 boxes of potatoes.
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The dot plot below shows the number of cakes 31 chefs made in a week: Dot plot labeled Number of Cakes Made shows 4 dots over 1,
Paraphin [41]
The median, because the data is not symmetric and there are outliers is the data is not symmetric and there are outliers.

The median of the data set is 8 cakes, while the average is 7.5.

However, 21 of the 31 chefs, or roughly 2/3, made 8 or more cakes. This makes the median a better center for this data, since the data is clearly skewed. The four chefs that made 1 cake each brings the average down, skewing the mean and making the median a better representation of the data. 
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3 years ago
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what is the perimeter measured in centimeters of the rectangle pictured below do not include units in your answer
Snezhnost [94]

Answer:

183

Step-by-step explanation:

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3 years ago
Suppose that you are in charge of evaluating teacher performance at a large elementary school. One tool you have for this evalua
Strike441 [17]

Answer:

a) Standard error = 2

b) Range = (76.08, 83.92)

c) P=0.69

d) Smaller

e) Greater

Step-by-step explanation:

a) When we have a sample taken out of the population, the standard error of the mean is calculated as:

\sigma_m=\dfrac{\sigma}{\sqrt{n}}=\dfrac{10}{\sqrt{25}}=\dfrac{10}{5}=2

where n is te sample size (n=25) and σ is the population standard deviation (σ=10).

Then, the standard error of the classroom average score is 2.

b) The calculations for this range are the same that for the confidence interval, with the difference that we know the population mean.

The population standard deviation is know and is σ=10.

The population mean is M=80.

The sample size is N=25.

The standard error of the mean is σM=2.

The z-value for a 95% confidence interval is z=1.96.

The margin of error (MOE) can be calculated as:

MOE=z\cdot \sigma_M=1.96 \cdot 2=3.92

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 80-3.92=76.08\\\\UL=M+t \cdot s_M = 80+3.92=83.92

The range that we expect the average classroom test score to fall 95% of the time is (76.08, 83.92).

c) We can calculate this by calculating the z-score of X=79.

z=\dfrac{X-\mu}{\sigma}=\dfrac{79-80}{2}=\dfrac{-1}{2}=-0.5

Then, the probability of getting a average score of 79 or higher is:

P(X>79)=P(z>-0.5)=0.69146

The approximate probability that a classroom will have an average test score of 79 or higher is 0.69.

d) If the sample is smaller, the standard error is bigger (as the square root of the sample size is in the denominator), so the spread of the probability distribution is more. This results then in a smaller probability for any range.

e) If the population standard deviation is smaller, the standard error for the sample (the classroom) become smaller too. This means that the values are more concentrated around the mean (less spread). This results in a higher probability for every range that include the mean.

6 0
3 years ago
Please help me with this question
WITCHER [35]

Answer:

you can't cheat in an online school math test =_=

Step-by-step explanation:

4 0
4 years ago
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