The percent yield for this reaction is 91%.
<u>Explanation</u>:
Ba(NO3)2 + Na2SO4 — > BaSO4 + 2NaNO3
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Assume that 0.45 mol of Ba(NO3)2 reacts with excess Na2SO4 to create 0.41 mol of BaSO4.
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Convert to grams of BaSO4 utilizing its molar mass (233.38 g/mol), which will be giving the actual yield.
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Actual Yield = 0.41 mol BaSO4 x (233.38 g BaSO4/1 mol BaSO4)
= 96 g BaSO4
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Beginning with 0.45 mol of Ba(NO3)2, compute the theoretical yield of BaSO4. Mole proportion of Ba(NO3)2 to BaSO4 is 1:1.
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0.45 mol Ba(NO3)2 x (1 mol BaSO4/1 mol Ba(NO3)2) x (233.38 g BaSO4/1 mol BaSO4) = 105 g BaSO4
% Yield = (Actual Yield/Theoretical Yield) x 100%
= (96/105) x 100%
= 91%.
Answer:
D. As water flows through the channels toward the turbines, it has kinetic energy. This is changed to mechanical energy as the water turns the turbines. Then the mechanical energy of the turbines is changed to electrical energy by the generator.
Explanation:
I hope this helps. :)
The charge is a little negative
Answer:
4 mol of Al₂O₃ are produced from 8 mole of Al
Explanation:
The reaction:
4 Al + 3O₂ → 2Al₂O₃
Ratio is 4:2
So, If we have 8 mol of Al, we will produce 4 mol of Al₂O₃