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Ksju [112]
3 years ago
6

Fill in the [?]: 12,341 us = [?] S

Chemistry
1 answer:
BigorU [14]3 years ago
3 0
Currency, is my best assumption without a subject to determine.
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When heated, calcium carbonate goes through a chemical reaction, and produces calcium oxide (quick lime) powder and carbon
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Carbon dioxide is produced, and as a gas, it was not captured to measure its mass.

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What does "hidden phenomena" mean in science?
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A balanced chemical equation must have the same number of which of these on both sides of the equation?
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A mixture of CO2 and Kr weighs 41.0 g and exerts a pressure of 0.729 atm in its container. Since Kr is expensive, you wish to re
Elena-2011 [213]

Answer:

a) 24.31 g

b) 16.69 g

Explanation:

A mixture of CO2 and Kr weighs 41.0 g and exerts a pressure of 0.729 atm in its container.

After the CO2 is completely removed by absorption with NaOH(s), the pressure in the container is 0.193 atm.

Therefore, Pressure of Kr = 0.193 atm

Pressure of CO2  = 0.729 - 0.193 = 0.536 atm

Their mole fraction can be also determined as follows:

CO2 = \frac{Presssure due to CO_2}{Total pressure}

CO2 = \frac{0.536}{0.729}

= 0.735

Also; for Kr ; we have

Kr = \frac{0.193}{0.729}

Kr = 0.265

Molar mass of CO2 = 44 g/mol

Molar mass of Kr = 83.78 g/mol

Mass of CO2 = mole fraction * molar mass = 0.735 * 44 = 32.34

Mass of Kr = 0.265 *  83.78 = 22.20

Total mass = 32.34 +22.20 = 54.54

The Percentage of gas in mixture is  as follows:

% CO2 = \frac{32.34}{54.54}* 100 %

= 0.5930

= 59.30%  

(a) Mass of CO2 in mixture = 0.5930* 41 g = 24.31 g

% Kr =\frac{22.20}{ 54.54} * 100 %

= 0.407

= 40.70 %

(b) Mass of Kr in mixture = 0.407 * 41 = 16.69 g

4 0
4 years ago
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