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3 years ago

Calculate the mass, in grams, of Al(OH)3 required for this reaction:

Chemistry

1 answer:

AVprozaik [17]3 years ago

3 0

Answer:

Mass = 28.08

Explanation:

Given data:

Mass of Al₂O₃ = 21.8 g

Mass of water = 9.7 g

Mass of Al(OH)₃ = ?

Solution:

Chemical equation:

2Al(OH)₃ → Al₂O₃ + 3H₂O

Number of moles of water:

Number of moles = mass/molar mass

Number of moles = 9.7 g/ 18 g/mol

Number of moles = 0.54 mol

Number of moles of Al₂O₃:

Number of moles = mass/molar mass

Number of moles = 21.8 g/ 101.96 g/mol

Number of moles = 0.21 mol

Now we will compare the moles of Al(OH)₃ with Al₂O₃ and H₂O.

Al₂O₃ : Al(OH)₃

1 : 2

0.21 : 2×0.21 = 0.42 mol

H₂O : Al(OH)₃

3 ; 2

0.54 : 2/3×0.54 = 0.36 mol

Mass of Al(OH)₃:

Mass = number of moles × molar mass

Mass = 0.36 mol × 78 g/mol

Mass = 28.08 g

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