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2 years ago

14

A jogger runs 8 miles north and then 5 miles west. What is the shortest distance, to the nearest tenth of a mile, he must travel

north to return to his starting point? I’ll give brainliest

1 answer:

Stells [14]2 years ago

5 0

Answer:

most likely has to run 13 miles southeast or 5 miles east and 8 west

Step-by-step explanation:

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2 years ago

If triangle ABC, m B = 90°, cos(9 = 17, and AB = 16 units.

Fed [463]

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m∠A = 62°

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Step-by-step explanation:

In the given triangle ABC,

m∠B = 90°, Cos(C) = $\frac{15}{17}$ and AB = 16 units

Since, Cos(C) = $\frac{\text{Corresponding side}}{\text{Hypotenuse}}$

Cos(C) = $\frac{\text{Corresponding side}}{\text{Hypotenuse}}=\frac{15}{17}$

$\text{C}=\text{Cos}^{-1}(\frac{15}{17})$

m∠C = 28.07°

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= $\frac{15}{17}$

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A = 61.93°

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3 years ago