The volume of pyramid B (3,136 in.³) is 323% bigger than the volume of pyramid B (972 in.³).
<h3>What is the Volume of a Square Pyramid?</h3>
Volume of square pyramid = 1/3(a²)h
Given the following:
- Volume of pyramid B = 3,136 in.³
- Base side length of pyramid A (a) = 18 in.
- Height of pyramid A (h) = 9 in.
Volume of square pyramid A = 1/3(a²)h = 1/3(18²)9 = 972 in.³
3,136/972 × 100 = 323%
Pyramid B volume is 323% bigger than the volume of pyramid A.
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We know that
Applying the law of cosines
c²=a²+b²-2*a*b*cos
C------> cos C=[a²+b²-c²]/[2*a*b]
in this problem
a=7.6 in
b=8.6 in
c=7.4 in
C=angle V
cos C=[7.6²+8.6²-7.4²]/[2*7.6*8.6]----> 0.5887
C=arc cos (0.5887)--------> C=53.93°-------> C=53.9°
the answer is
angle V is 53.9°
Answer:
<h2>A. 4t² - 32t + 64</h2>
Step-by-step explanation:
Instead of x put (t - 3) in the equation of the function f(x) = 4x² - 8x + 4:
f(t - 3) = 4(t - 3)² - 8(t - 3) + 4
<em>use (a - b)² = a² - 2ab + b² and the distributive property a(b + c) = ab + ac</em>
f(t - 3) = 4(t² - (2)(t)(3) + 3²) + (-8)(t) + (-8)(-3) + 4
f(t - 3) = 4(t² - 6t + 9) - 8t + 24 + 4
f(t - 3) = (4)(t²) + (4)(-6t) + (4)(9) - 8t + 28
f(t - 3) = 4t² - 24t + 36 - 8t + 28
f(t - 3) = 4t² + (-24t - 8t) + (36 + 28)
f(t - 3) = 4t² - 32t + 64
Answer:
No, they are not.
Step-by-step explanation: can I get brainlest?
Answer:
b = 5.
Step-by-step explanation:
-3(6 + 6b) + 4 = -104
-18 - 18b + 4 = -104
-18b = -104 + 18 - 4
-18b = -90
b = -90 / -18
b = 5.
