This problem here would be a little tricky. Let us take into account first the variables presented which are the following: a collection of triangular and square tiles, 25 tiles, and 84 edges. Triangles and squares are 2D in shape so they give us a variable of 3 and 4 to work on those edges. Let us say that we represent square tiles with x and triangular tiles with y. There would be two equations which look like these:
x + y = 25 and 4x + 3y = 84
The first one would refer to the number of tiles and the second one to number of edges.
We will be using the first equation to the second equation and solve for one. So if we will be looking for y for instance, then x in the second equation would be substituted with x = 25 - y which would look like this:
4 (25 - y) + 3y = 84
Solve.
100 - 4y + 3y = 84
-4y +3y = 84 - 100
-y = -16
-y/-1 = -16/-1
y = 16
Then:
x = 25 -y
x = 25 - 16
x = 9
So the answer is that there are 9 square tiles and 16 triangular tiles.
Answer:
y=2205
Step-by-step explanation:
5+y-5/34+3*7-6=45
combine terms on each side
y/49=45
multiply 49 on each side
y=2205
i hope this helps you
Answer: speed is 540 km/h
Step-by-step explanation: Lets mark speed as v.
Because distenace is same, you can mark 6 h · 900 km/h = 10 h · v
and v = 5400 km / 10 h = 540 km/h.
Or using inverse proportions : 10 h / 6 h = v / 900 km/h .
Before multiplying you turn lastproportion around :
10 h / 6 h = 600 km/ h / v ,which gives 10 v = 6 · 900 km/h
and result is same
Answer:
f(x)=x^2
Step-by-step explanation:
if you wanted have a function where both of the robot's arms are in the air the function could be x to the power of any even number such f(x)=x^2, f(x)=x^4, f(x)=x^6, or even f(x)=x^10. And you could still do the same transformations with these equations.
Answer:
Regular Octagon
Step-by-step explanation:
There are only three regular shapes that tessellate – the square, the equilateral triangle, and the regular hexagon. All other regular shapes, like the regular pentagon and regular octagon, do not tessellate on their own.
