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IgorLugansk [536]
3 years ago
6

Two galaxies are shown. Galaxy U: Dust, gas, and stars in the shape of a pinwheel, relatively small in size. Galaxy NGC 1427A: D

ust, gas, and stars in a nonuniform arrangement spread out over a large area. How are NGC 1427A and U different? How are they the same?
Mathematics
2 answers:
Pani-rosa [81]3 years ago
8 0

Answer:

NGC 1427A has no general shape, so it is an irregular galaxy. U has a bulge in the center and arms, so it is a spiral galaxy. They are similar in that both contain plenty of dust and gas. Both also have active star-forming sites.

Step-by-step explanation: Got it right on the test

anzhelika [568]3 years ago
6 0

Answer:

NGC 1427A has no general shape, so it is an irregular galaxy. U has a bulge in the center and arms, so it is a spiral galaxy. They are similar in that both contain plenty of dust and gas. Both also have active star-forming sites.

Step-by-step explanation:

i got it right.

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A large university accepts ​60% of the students who apply. Of the students the university​ accepts, ​30% actually enroll. If 30,
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60% apply means 30k *0.6= 18000

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I need help 20 pts thx look at the image
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Answer:

Factors are numbers you can multiply to get each number. For example, for 30 you would have factors of 1, 2, 3, 5, 6, 10, 15, and 30.  I got that because 1 x 30 = 30, 2 x 15=30, 3 x 10 = 30, and 5 x 6= 30.  If the factors are just 1 and that number it is prime.  If there are other factors, it is composite.  30 would be composite.

Step-by-step explanation:

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25 points plus will mark brainliest!!!<br><br>Find angle ABD.<br>​
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Which of the following situations would best be modeled by a discrete relationship? a. A teacher counts the number of students i
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Option d is correct.

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What is 4log1/2^w(2log1/2^u-3log1/2^v written as a single logarithm?
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Given:

4log1/2^w (2log1/2^u-3log1/2^v)

Req'd:

Single logarithm = ?

Sol'n:

First remove the parenthesis,

4 log 1/2 (w) + 2 log 1/2 (u) - 3 log 1/2 (v)

Simplify each term,

Simplify the 4 log 1/2 (w) by moving the constant 4 inside the logarithm;
Simplify the 2 log 1/2 (u) by moving the constant 2 inside the logarithm;
Simplify the -3 log 1/2 (v) by moving the constant -3 inside the logarithm:

 log 1/2 (w^4)  + 2 log 1/2 (u) - 3 log 1/2 (v) 
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Log of 1/2 (w^4 u^2) - log of 1/2 (v^3) 

then use the quotient property of logarithms which is log of b (x)  - log of b (y) = log of b (x/y)

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log of 1/2 (w^4 u^2 / v^3)

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