PH is logarithmically related to the concentration of H+ ions. This will be the formula that will be used for this problem. We calculate as follows:
HCN = H+ + CN-
1.85 g HCN ( 1 mol / 27.02 ) ( 1 mol H+ / 1 mol HCN ) = 0.068 mol H+
Concentration = 0.068 / 3.50 = 0.02 M
pH = -log 0.02
pH = 1.71
Answer:
1.54 ml
2. 54 g
3. -43.7 °C
4. 97 g
5. 17.74 kJ
Explanation:
1. Volume of water that only came from the melted ice is;
Volume of water plus melted ice-volume of warm water
151 ml - 97 ml = 54 ml
2.Mass of water that came from the melted ice.
Mass=density of water * volume of water from melted ice
M=1 g/ml * 54 ml = 54 g
3. The change in temperature of warm water will be;
Lowest temperature of ice-water mixture-Temperature of warm water
ΔT=0.9-44.6 = -43.7
4. Mass of warm water will be;
Mass of warm water= density of water*volume of warm water
M=1g/ml * 97 = 97 g =0.097 kg
5.
Energy released by warm water as it cools
Q=mcΔT
Given , mass of warm water=m=97
c=4.184 j/g*°C = 4184 J/(kg.C)
Δ= - 43.7
Q=0.097*4184*43.7 =17735.56 J
17735.56/1000 =17.74 kJ
J. J. Thomson - oil drop
Albert Einstein - atomic theory
Niels Bohr - model of the atom
Ernest Rutherford - gold foil experiment
John Dalton - cathode ray tube
Robert Millikan - photoelectric effect
Answer:
could you explain your question more
Explanation: