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Ilia_Sergeevich [38]
3 years ago
7

Which table best summarizes the subatomic particles and their electrical charge?

Chemistry
1 answer:
Tanzania [10]3 years ago
4 0

Answer:

Proton   -  Positive charge

Neutron - No charge

Electron - negative charge

Explanation:

An atom is the smallest particle of matter that takes part in a chemical reaction.

It is made up of three fundamental subatomic particles.

  1. Protons are the positively charged particles in an atom.
  2. Neutrons do not carry any charges and are neutral
  3. Electrons are negatively charged

Both the protons and neutrons occupy a tiny center where the mass of the atom is concentrated. The region is called the nucleus.

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2 HI(g) = H2(g) + 1,(9) K, - Party met = 0.0016 The decomposition of HI(g) at 298 K is represented by the equilibrium equation a
givi [52]

Answer:

(C) P = 7.4 torr, because it is directly proportional to the initial pressure of HI.

Explanation:

From the equation of reaction,

Kc = [H2][I2]/[HI]^2

Kc = 0.0016

Initial pressure of HI = 200 torr

Let the equilibrium pressure of I2 be y

Mole ratio of H2 to I2 from the equation of reaction is 1:1, equilibrium pressure of H2 is also y

Mole ratio of HI to I2 is 2:1, equilibrium pressure of HI is (200 - 2y)

0.0016 = y×y/(200 - 2y)^2

y^2 = 0.0016(40,000 - 800y + 4y^2)

y^2 = 64 - 1.28y + 0.0064y^2

y^2 - 0.0064y^2 + 1.28y - 64 = 0

0.9936y^2 + 1.28y - 64 = 0

y^2 + 1.29y - 64.41 = 0

The value of y must be positive and is obtained by the use of the quadratic formula.

y = [-1.29 + sqrt(1.29^2 - 4×1×-64.41)] ÷ 2(1) = [-1.29 + 16.10] ÷ 2 = 14.81 ÷ 2 = 7.4

Equilibrium pressure of I2 is 7.4 torr because the relationship between I2 and HI is direct in which increase in one quantity (initial pressure of HI) would result to a corresponding increase in the other quantity (equilibrium pressure of I2)

3 0
4 years ago
Okay so this is half math half chemistry...
AleksandrR [38]
So you need to find the volume in L? If so:
Convert the mass of Lithium Bromide into moles by dividing the 100 grams by the molar mass of LiBr, taken from the periodic table 
In a solution, moles = (concentration in mole/L) x (volume in L)
We know the moles, we have the concentration in mole/L, now find the volume in L, and you should get 0.288. Plz do the math and check for yourself
3 0
3 years ago
For centuries, sailors used tree sap (pitch) to seal the spaces between the planks on wooden boats. Explain why pitch worked wel
o-na [289]
Tree sap is a viscoelastic polymer, which means it's not really a solid but a very viscous (sticky) fluid. It's fluidity ensures that it can properly <span>seal the spaces between the planks on wooden boats. Not only that, the pitch sap is hydrophobic - it is water resistant as well. </span>
5 0
4 years ago
4. Naming Molecules<br> a) Describe how ionic bonds are formed at the atomic level.
RoseWind [281]

Explanation:

Ionic bonds involve a cation and an anion. The bond is formed when an atom, typically a metal, loses an electron or electrons, and becomes a positive ion, or cation. Another atom, typically a non-metal, is able to acquire the electron(s) to become a negative ion, or anion.

8 0
3 years ago
Photosynthesis reactions in green plants use carbon dioxide and water to produce glucose (C6H12O6) and oxygen. A plant has 88.0
grandymaker [24]

The given question is incomplete. The complete question is:

Photosynthesis reactions in green plants use carbon dioxide and water to produce glucose (C6H12O6) and oxygen. A plant has 88.0 g of carbon dioxide and 64.0 g of water available for photosynthesis. Determine the mass of glucose (C6H1206) produced

Answer: 60.0 g of glucose

Explanation:

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

a) moles of CO_2

\text{Number of moles}=\frac{88.0g}{44g/mol}=2.0moles

b) moles of H_2O

\text{Number of moles}=\frac{64.0g}{18g/mol}=3.5moles

6CO_2+6H_2O\rightarrow C_{6}H_{12}O_6+6O_2

According to stoichiometry :

6 moles of CO_2 require = 6 moles of H_2O

Thus 2.0 moles of CO_2 require=\frac{6}{6}\times 2.0=2.0moles  of H_2O

Thus CO_2 is the limiting reagent as it limits the formation of product.

As 6 moles of CO_2 give =  1 moles of glucose

Thus 2.0 moles of CO_2 give =\frac{1}{6}\times 2.0=0.33moles  of glucose

Mass of glucose = moles\times {\text {Molar mass}}=0.33moles\times 180g/mol=60g

Thus 60.0 g of glucose will be produced from 88.0 g of carbon dioxide and 64.0 g of water  

8 0
3 years ago
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