Use the equation below to determine how many grams of CO are needed to react with an excess of Fe2O3 to produce 104.9 g Fe? You

Question

3 years ago

14

Use the equation below to determine how many grams of CO are needed to react with an excess of Fe2O3 to produce 104.9 g Fe? You

must show all of your work to receive credit.
Molar Mass Information:
Fe= 55.85 g/mol
C= 12.01 g/mol
O= 15.99 g/mol
(3 points)

Please I'm so confused!!!

Chemistry

2 answers:

patriot [66] · Answer 1 · 2022-05-21T22:54:10+03:00

patriot [66]3 years ago

7 0

Answer:

1.40 * 10 ^3 g

Explanation:

Fynjy0 [20] · Answer 2 · 2022-05-22T00:24:51+03:00

Answer:

78.89g

Explanation:

3CO+Fe2O3=2fe+3CO2 from the equation. 3moles of CO produced 2moles of Fe thus. Molar mass of CO=28 and Fe=55.85. Going by the formulae n= mass/molar mass. Mass of each will be n× molar mass. Thus. 28×3=84. 55.85×2=111.7. Thus,111.7g was produced by 84g of CO. Then 104.9g of Fe will be produced by 84/111.7×104.9=78.89g