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BartSMP [9]
3 years ago
6

PLEASE MATH HELP WILL GIVE BRAINLIEST!

Mathematics
2 answers:
ruslelena [56]3 years ago
8 0
1. y=-3/4x+23/2
2. y=-x/3+10/3
katrin2010 [14]3 years ago
3 0
The answer to 2 is y = -3x + 14
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what is the total price of a book if barnes and nobles gets it for 4.25 and the markup is 30% How much do they sell the book for
7nadin3 [17]

Answer:

$5.53 i think

Step-by-step explanation:

30% = 0.3

0.3 x 4.25 = 1.275

1.275 + 4.25  ≈ 5.53

8 0
3 years ago
Read 2 more answers
Suppose Metro by T-Mobile wants to offer a simple extended warranty plan. If your phone is damaged, they will repair it for up t
MAXImum [283]

Answer:

45

Step-by-step explanation:

Given that :

Voucher awarded (x) :

Repair = $50

Lose or destroy = $200

P(x):

Replacement voucher = 5%

Repair voucher = 10%

X ______ 50 ______ 200

P(x) ____ 0.1 _______ 0.05

Expected variance Var(X) :

ΣX²p(x) - E(x) ;

E(x) = Σx*p(x) = (50*0.1) + (200*0.05) = 15

ΣX²p(x) = Σ[(50^2 * 0. 1) + (200^2 * 0.05)] = 250 + 2000 = 2250

Var(X) = 2250 - 15^2 = 2025

Standard deviation = √Var(x)

Standard deviation = √2025

Standard deviation = $45

4 0
3 years ago
One endpoint of a line segment is (-6,4) the midpoint(-2,7) (What are the coordinates of the other endpoint? PLEASE HELP !!
mina [271]
A.) (2, 10), add -6 to -2 to give you 4 units. Then add 4 to the midpoint(-2, and 7), and you end up with 2 and 3. Then just add 3 to seven and you have the coordinates of (2, 10), hope this helps!
3 0
3 years ago
Solve the system. <br> x+3y=1 <br> -2x+7=-23
Viefleur [7K]
X+ 3y = 1  -----(first equation)
-2x+7 = -23 ---(second equation)
-2x = -23-7
x = 30/2
x = 15

Now, Substitute the value of x in first equation,
15 + 3y = 1
3y = 1 - 15
y = -14/3

In short, Final Answers are: x = 15 & y = -14/3

Hope this helps!
5 0
3 years ago
Label the equations in number 5-7 as True or False:
kkurt [141]

Answer:

{ \rm{ {(7}^{1}) ^{9    }  = 7 {}^{5} \times  {7}^{5}  :   \: { \tt{ \red{false}}} }} \\{ \boxed{ \mathfrak{correction \dashrightarrow \: ( {7}^{1}) {}^{9}  =  {7}^{9}  }}} \\ \\  { \rm{ \frac{ {y}^{13} }{ {( {y}^{2}) }^{6} } =  {y}^{ - 10}   \times  {y}^{9}  :  \:{ \tt { \red{false}}}}} \\ { \boxed{ \mathfrak{correction \:  \dashrightarrow \:  { \rm{{y}^{1} }}}}} \\  \\ { \rm{ {b}^{4}  \times  {b}^{ - 6}  =   \frac{ {b}^{1}  \times  {b}^{3} }{ {b}^{6} } }} \:  :  \: { \tt{ \green{true}}}

8 0
3 years ago
Read 2 more answers
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