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3 years ago

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1. Lois has 10 coins in quarters and dimes in their pocket. After counting, the total value is $1.45. How many of each coin did

Lois have?

2 answers:

LenaWriter [7]3 years ago

5 0

Answer: she had five quarters and 2 dimes

Step-by-step explanation:

Jet001 [13]3 years ago

3 0

Answer:

5 quarters and 2 dimes

Step-by-step explanation:

5 quarters make 1.25 + 10 cents = 1.45

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ddd [48]

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3 years ago

Suppose that \nabla f(x,y,z) = 2xyze^{x^2}\mathbf{i} + ze^{x^2}\mathbf{j} + ye^{x^2}\mathbf{k}. if f(0,0,0) = 2, find f(1,1,1).

lesya [120]

The simplest path from (0, 0, 0) to (1, 1, 1) is a straight line, denoted $C$ , which we can parameterize by the vector-valued function,

$\mathbf r(t)=(1-t)(\mathbf i+\mathbf j+\mathbf k)$

for $0\le t\le1$ , which has differential

$\mathrm d\mathbf r=-(\mathbf i+\mathbf j+\mathbf k)\,\mathrm dt$

Then with $x(t)=y(t)=z(t)=1-t$ , we have

$\displaystyle\int_{\mathcal C}\nabla f(x,y,z)\cdot\mathrm d\mathbf r=\int_{t=0}^{t=1}\nabla f(x(t),y(t),z(t))\cdot\mathrm d\mathbf r$

$=\displaystyle\int_{t=0}^{t=1}\left(2(1-t)^3e^{(1-t)^2}\,\mathbf i+(1-t)e^{(1-t)^2}\,\mathbf j+(1-t)e^{(1-t)^2}\,\mathbf k\right)\cdot-(\mathbf i+\mathbf j+\mathbf k)\,\mathrm dt$

$\displaystyle=-2\int_{t=0}^{t=1}e^{(1-t)^2}(1-t)(t^2-2t+2)\,\mathrm dt$

Complete the square in the quadratic term of the integrand: $t^2-2t+2=(t-1)^2+1=(1-t)^2+1$ , then in the integral we substitute $u=1-t$ :

$\displaystyle=-2\int_{t=0}^{t=1}e^{(1-t)^2}(1-t)((1-t)^2+1)\,\mathrm dt$

$\displaystyle=-2\int_{u=0}^{u=1}e^{u^2}u(u^2+1)\,\mathrm du$

Make another substitution of $v=u^2$ :

$\displaystyle=-\int_{v=0}^{v=1}e^v(v+1)\,\mathrm dv$

Integrate by parts, taking

$r=v+1\implies\mathrm dr=\mathrm dv$

$\mathrm ds=e^v\,\mathrm dv\implies s=e^v$

$\displaystyle=-e^v(v+1)\bigg|_{v=0}^{v=1}+\int_{v=0}^{v=1}e^v\,\mathrm dv$

$\displaystyle=-(2e-1)+(e-1)=-e$

So, we have by the fundamental theorem of calculus that

$\displaystyle\int_C\nabla f(x,y,z)\cdot\mathrm d\mathbf r=f(1,1,1)-f(0,0,0)$

$\implies-e=f(1,1,1)-2$

$\implies f(1,1,1)=2-e$

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3 years ago

If someone could help me with this problem

liraira [26]

The equation of the given Absolute Value Function is; y = |-2x + 4|

<h3>How to interpret Linear Graphs?</h3>

We can see that the given graph is a Linear graph but since it is V-shaped, we can say that it is a graph of an absolute value function.

Now, from the graph we see that;

At x = 0, y = 4

At x = 1, y = 2

At x = 2, y = 0

At x = 3, y = -2

At x = 4, y = 0

At x = 5, y = 2

We can see that the y-intercept is at y = 4.

Slope between two consecutive points is;

(2 - 4)/(1 - 0) = -2

Equation is; y = -2x + 4

Now, this is an absolute value function and as such we will write it as;

y = |-2x + 4|

Read more about Linear Graphs at; brainly.com/question/4025726

#SPJ1

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2 years ago