Answer:
K = kg/m
Explanation:
as velocity has units of m/s V³ has units of m³/s³
power has units of J/s = N•m/s = kg•m/s²•m/s = kg•m²/s³
kg•m²/s³ = K(m³/s³)
K = kg•m²/s³•s³/m³
K = kg/m
Answer:
As each mower presumably needs the same torque to start, and torque is a product of force and moment arm, the longer moment arm of 10.42 cm on Uwi's mower means lower force is required when compared to Urippe's shorter moment arm of 1.35 cm
350 rev/min = 350(2π) / 60 = 36.652 rad/s
36.652 rad/s / 0.294 s = 124.66... <u>125 rad/s²</u>
a = αR = 125(0.1042) = 12.990... <u>13 m/s²</u>
a = αR = 125(0.0135) = 1.68299... <u>1.7 m/s²</u>
I am GUESSING that we are supposed to model these mowers as a uniform disk
τ = Iα
FR = (½mr²)α
F = mr²α/2R
Urippe's pull = (3.56)(0.2041²)(124.66) / (2(0.0135)) = 702.008... <u>702 N</u>
Usi's pull = (3.56)(0.2041²)(124.66) / (2(0.1042)) = 90.9511...<u>91.0 N</u>
L = Iω = (½(3.56)(0.2041²))36.652 = 2.71771...<u>2.72 kg•m²/s down</u>
using the right hand rule
Answer:
force acting on the parent = 25 N .
Explanation:
According to third law of Newton , there is equal and opposite reaction to every action . Here force by the parent on child is action and the force by child on parent is reaction . The former is given as 25 N so force by child on parent will also be 25 N .
Answer is 25 N .
Answer:
F = -8440.12 N
the magnitude of the average force needed to hold onto the child is 8440.12 N
Explanation:
Given;
Mass of child m = 16 kg
Speed of each car v = 59.0 mi/h = 26.37536 m/s
Time t = 0.05s
Applying the impulse momentum equation;
Impulse = change in momentum
Ft = ∆(mv)
F = ∆(mv)/t
F = m(∆v)/t
Where;
F = force
t = time
m = mass
v = velocity
Since the final speed of the car is zero(at rest) then;
∆v = 0 - v = -26.37536 m/s
Substituting the given values;
F = 16×-26.37536/0.05
F = -8440.1152 N
F = -8440.12 N
the magnitude of the average force needed to hold onto the child is 8440.12 N
Answer:
Explanation:
Use the Kinematic Equation:
Plug in what is given and solve
