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aniked [119]
3 years ago
15

How does the physical structure of a plant have Large leaves help it survive?

Physics
1 answer:
elena-14-01-66 [18.8K]3 years ago
3 0

The large leaves help it survive as they serve as the<u> organ for photosynthesis.</u>

Explanation:

  • Photosynthesis, the process by which green plants and certain other organisms transform light energy into chemical energy.
  • During photosynthesis in green plants, light energy is captured and used to convert water, carbon dioxide, and minerals into oxygen and energy-rich organic compounds
  • Leaves provide food and air to help a plant stay healthy and grow. Through photosynthesis, leaves turn light energy into food.
  • Through pores, or stomata, leaves breathe in carbon dioxide and breathe out oxygen. Leaves also release excess water.
  • Most leaves are broad and so have a large surface area allowing them to absorb more light
  • A thin shape means a short distance for carbon dioxide to diffuse in and oxygen to diffuse out easily.
  • The exchange of oxygen and carbon dioxide in the leaf occurs through pores called stomata.
  • Normally stomata open when the light strikes the leaf in the morning and close during the night.

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Answer:
d = 3.8857 g/cm^3

Explain:
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4 0
3 years ago
What is the total entropy change if a 0.280 efficiency engine takes 3.78E3 J of heat from a 3.50E2 degC reservoir and exhausts i
babymother [125]

Answer:

\Delta S=1.69J/K

Explanation:

We know,

\eta=1-\frac{T_2}{T_1}=1-\frac{Q_2}{Q_1}      ..............(1)

where,

η = Efficiency of the engine

T₁ = Initial Temperature

T₂ = Final Temperature

Q₁ = Heat available initially

Q₂ = Heat after reaching the temperature T₂

Given:

η =0.280

T₁ = 3.50×10² °C = 350°C = 350+273 = 623K

Q₁ = 3.78 × 10³ J

Substituting the values in the equation (1) we get

0.28=1-\frac{Q_2}{3.78\times 10^{3}}

or

\frac{Q_2}{3.78\times 10^3}=0.72

or

Q_2=3.78\times 10^3\times0.72

⇒ Q_2 =2.721\times 10^3 J

Now,

The entropy change (\Delta S) is given as:

\Delta S=\frac{\Delta Q}{T_1}

or

\Delta S=\frac{Q_1-Q_2}{T_1}

substituting the values in the above equation we get

\Delta S=\frac{3.78\times 10^{3}-2.721\times 10^3 J}{623K}

\Delta S=1.69J/K

7 0
3 years ago
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