Let's start by differentiating the terms distance and displacement. They both refer to the length of paths. Distance only accounts for the total length regardless of the path taken. Displacement measures the linear path from the starting point to the end point. So, it does not necessarily follow the actual path. However, for this problem, assuming that the path is just in one direction, displacement and distance would just be equal. The equation would be:
Distance = Displacement = v₀t + 0.5at² = 0(10 s) + 0.5(+1.2 m/s²)(10 s)²
Distance = Displacement = 60 meters
Answer:
a
b
Explanation:
From the question we are told that
The spring constant is
The mass of the block is
Considering question a
Generally the weight of the block is mathematically represented as
=>
=>
Generally the force exerted on the spring is mathematically represented as
At equilibrium
=>
=>
=>
Considering question b
Generally the energy stored in the spring is mathematically represented as
Now the potential energy of the block before it is drooped is mathematically represented as
Generally from the law of energy conservation we have that
=>
=>
=>
Answer:
1.After 11 hours, the cruise ship will be _233.75__nautical miles from the lighthouse.
2.At the start of the journey, the cruise ship was _10.5__
nautical miles from the lighthouse.
3.The cruise ship is traveling at a speed of_21.25_ nautical miles per hour.
Explanation:
Distance covered in 2 hours= 95.5-53NM
=42.5NM
therefore,
put value of distance and time in equation (1)
therefore,
speed=21.25NM/hour
Therefore distance covered in 11 hours= speed* time
=233.75NM
2. Since distance covered in 2 hours is 42.5
therefore, at starting of the journey the cruise distance from light house is
= 53NM-42.5NM
=10.5NM
3. Distance covered in 2 hours= 95.5-53NM
=42.5NM
therefore,
put value of distance and time in equation (1)
therefore,
speed=21.25NM/hour
Therefore Cruise ship is traveling at speed of 21.25NM/hour
Answer:
amount of work done = -1.77 J
Explanation:
given data
mass = 0.25 kg
speed = 5 m/s
height = 2m
to find out
amount of work done by the water on the ball bearing
solution
we get here potential energy when ball fall
potential energy = mgh
potential energy = 0.25 × 9.8 × 2
potential energy = 4.9 J
and that lose potential energy gain by kinetic energy that is express as
kinetic energy = 0.5 × m × v²
kinetic energy = 0.5 × 0.25 × 5²
kinetic energy = 3.13 J
so we get now work done that is
work done = kinetic energy - potential energy
work done = 3.13 J - 4.9 J
amount of work done = -1.77 J