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3 years ago

17/19 is equal to what fraction A 80/95 B 43/57 C 50/57 D 85/95

Mathematics

2 answers:

Vadim26 [7]3 years ago

7 0

Answer:

D 85/95

Step-by-step explanation:

17/19

Multiply the top and bottom by 3

17/19 *3/3 =51/57

Multiply the top and bottom by5

17/19 *5/5 =85/95

leonid [27]3 years ago

7 0

Answer:

85/95

Step-by-step explanation:

1) lets simplify all the options and see if it equals 17/19

80/95=16/19

43/57=43/57(prime numbers)

50/57=50/57(no gcf)

85/95=17/19

Hope this helps

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Exponential Function assignments help please! ❤️

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Answer:

Initial value is 4,000

Growth is -480

Step-by-step explanation:

Initial value is the value that you started with: hence 4000.

Growth would be how much it grows, it grows downward because it is 12% down. Next you need to find what 13% of 4000 is 100%-13%=88% .88*4000=480 or 13% of 4000.

Hope this helps

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A ball with a rebound percentage of 45% was dropped from a height of 215feet. What is the height of the ball after the 5th bounc

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Step-by-step explanation:

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3 years ago

A survey of 865 voters in one state reveals that 408 favor approval of an issue before the legislature. Construct the 95% confid

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Answer:

The 95% confidence interval for the true proportion of all voters in the state who favor approval is (0.4384, 0.5050).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 865, \pi = \frac{408}{865} = 0.4717$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4717 - 1.96\sqrt{\frac{0.4717*0.5283}{865}} = 0.4384$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4717 + 1.96\sqrt{\frac{0.4717*0.5283}{865}} = 0.5050$

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3 years ago

What are the x and y intercepts of 3y=2x-6

sasho [114]

How to find the x intercept of 3y=2x-6: (when y is 0)

3(0) = 2x - 6

   0 = 2x - 6
+6 + 6
-------------------------
6 = 2x
  ------ -----
2    2

x = 3

How to find the y intercept of 3y=2x-6: (when x is 0)

3y = 2(0) - 6

y = 0 - 6

3y = -6
------ -----
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3 years ago

Suppose that there are five young women and six young men on an island. Each woman is willing to marry some of the men on the is

pochemuha

Answer:

Based on the current information, the last man remaining unmarried will be a choice between two

Jason marries Anna

Matt marries Elizabeth

Kevin marries Barbara

Larry marries Diane

Carol can marry either Nick or Oscar

Step-by-step explanation:

The basic method to sort which woman will be marrying which man is simple.

We have to extract the choice by comparing choices of each woman side by side and then selecting the least common one and hence sorting one by one.

First, let's name all the women and men

1. Anna

2. Barbara

3. Carol

4. Diane

5. Elizabeth

We will refer to them with the initial letter of their name . A for Anna, B for Barbara, C for Carol, D for Diane, E for Elizabeth.

The men :

1. Jason

2. Larry

3. Matt

4. Kevin

5. Oscar

6. Nick

And they will be referred as J for Jason, L for Larry, M for Matt, K for Kevin, O for Oscar and N for Nick.

Options for A : J , L ,M

Options for B : K, L

Options for C : J, N , O

Options for D : J, L , N , O

Options for E : J, M

As we can see , no one else wants Kevin other than Barbara so :

Kevin marries Barbara

Moving onwards:

Elizabeth can marry either Jason or Matt,

Meanwhile Anna can marry either Jason , Larry or Matt

Hence,

Matt marries Eilzabeth

as Anna has two more choices still which are Jason and Larry.

Further, seeing the options for Carol and Diane

Carol can marry either Jason, Nick or Oscar while Diane can marry Larry as well as Jason , Nick and Oscar

We can select Jason as the match for Anna as Larry is also a choice for Diane.

Hence, Jason marries Anna

Now we are left with Larry , Nick and Oscar.

Since Carol can only decide from Nick and Oscar but Diane can decide from Larry, Nick and Oscar. Larry is the ideal option for Diane

so, Larry marries Diane

Now in the end, Carol can either choose between Nick or Oscar.

If she chooses Nick to marry, Oscar is left single

If she chooses Oscar to marry, Nick is left single.

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3 years ago