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3 years ago

Find the solution of y = –x – 3 for x = 1.

Mathematics

1 answer:

nikklg [1K]3 years ago

5 0

Answer:

A. :)

Step-by-step explanation:

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Griffin ordered a pair of sneakers online. He had a $17 credit that he applied toward the purchase, and then he used a credit ca

MrMuchimi

Well it would be 63$ if we are not including tax because 80-17=63

4 0

2 years ago

Find the intercepts: x+5y= -5

devlian [24]

X=-5 and y=1

you would replace the letter x or y with zero to find the intercept.

5 0

2 years ago

If a student is 65.0 in tall, what is her height in m? (2.54 cm = 1 inch)

spayn [35]

Answer:

Height of the student=1.651m

Step-by-step explanation:

Given: Height of a student= 65.0 inch.

To find: Height of a student in meters.

Solution:

We know that 1 inch=2.54 cm, then

65.0 inch will be = $2.54{\times}65.0$

65.0 inch will be= $165.2 cm$

Also, we know that 1cm= $\frac{1}{100} m$ , then

165.2 cm will be equal to= $\frac{1}{100}{\times}165.1$

165.2 cm will be equal to= $1.651 meters$

Therefore, the height of a student in meters will be 1.651 meters.

5 0

2 years ago

Can someone PLEASE help me with Trigonometry???

Svetach [21]

$\bf sin^2(2\theta)-7sin(2\theta)-1=0\\\\
-------------------------------\\\\
sin(2\theta)=\cfrac{7\pm\sqrt{49-4(1)(-1)}}{2(1)}\implies sin(2\theta)=\cfrac{7\pm\sqrt{49+4}}{2}
\\\\\\
sin(2\theta)=\cfrac{7\pm\sqrt{53}}{2}\implies 2\theta=sin^{-1}\left( \frac{7\pm\sqrt{53}}{2} \right)
\\\\\\
\theta=\cfrac{sin^{-1}\left( \frac{7\pm\sqrt{53}}{2} \right)}{2}$

but anyway, the numerator will give the angles, and θ is just half of each

$\bf \theta=\cfrac{sin^{-1}\left( \frac{7\pm\sqrt{53}}{2} \right)}{2}\\\\
-------------------------------\\\\
sin^{-1}\left( \frac{7+\sqrt{53}}{2} \right)\implies sin^{-1}(7.14)\impliedby \textit{greater than 1, no good}
\\\\\\
sin^{-1}\left( \frac{7-\sqrt{53}}{2} \right)\implies sin^{-1}(-0.14) \approx -8.05^o
\\\\\\
\theta=\cfrac{-8.05}{2}\implies \theta=-4.025$

ok... that's a negative tiny angle, is in the 4th quadrant, if we stick to the range given, from 0 to 360, so we have to use the positive version of it, 360-4.025

so the angle is 355.975°

now, the 3rd quadrant has another angle whose sine is negative, so... if we move from the 180° line down by 4.025, we end up at 184.025°

and those are the only two angles, because, on the 2nd and 1st quadrants, the sine is positive, so it wouldn't have an angle there

7 0

3 years ago

Pls help I need it done tonight

Ksenya-84 [330]

Answer:

ABD= 58

BDC= 32

Step-by-step explanation:

complementary = 2 angles equal 90 degrees.

8y+2=90

Subtract 2 both sides.

8y=88

y=11

That's not all, put y into the equations.

ABD

5(11)+3

Multiply

55+3=58

BDC

3(11)-1

MULTIPLY

33-1

SUBTRACT

4 0

2 years ago