The answer is 474 i believe
Answer:
<h2>2/5</h2>
Step-by-step explanation:
The question is not correctly outlined, here is the correct question
<em>"Suppose that a certain college class contains 35 students. of these, 17 are juniors, 20 are mathematics majors, and 12 are neither. a student is selected at random from the class. (a) what is the probability that the student is both a junior and a mathematics majors?"</em>
Given data
Total students in class= 35 students
Suppose M is the set of juniors and N is the set of mathematics majors. There are 35 students in all, but 12 of them don't belong to either set, so
|M ∪ N|= 35-12= 23
|M∩N|= |M|+N- |MUN|= 17+20-23
=37-23=14
So the probability that a random student is both a junior and social science major is
=P(M∩N)= 14/35
=2/5
Given:difference in the mean weight gain is 0.60 gramsstandard deviation of the difference in sample mean is 0.305
68% confidence interval for the population mean difference is a) 0.305
0.60 + 1 * 0.3050.60 + 0.305 = 0.9050.60 - 0.305 = 0.295
95% confidence interval for the population mean difference is c) 0.61
0.60 + 2 * 0.3050.60 + 0.61 = 1.210.60 - 0.61 = -0.01
