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3 years ago

14

Which expression has a value of 15, using only four 4s and any of the following: + , – , · , ÷, exponents, and/or parentheses? A

. 44 – (4 ÷ 4) B. (4 · 4) – (4 + 4) C. (4 · 4) – (4 ÷ 4) D. (4 + 4 + 4) ÷ 4

1 answer:

Simora [160]3 years ago

5 0

Hello :
<span>C.) (4 · 4) – (4 ÷ 4) =16-1=15</span>

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A regular polygon has an odd number of sides. Which statement is true about the lines of reflection for the polygon that will ma

UNO [17]

"The lines of reflection are parallel to the sides of the polygon" is the statement that is true about the lines of reflection for the polygon that will map the shape onto itself. The correct option among all the options that are given in the question is the third option or option "C". I hope that the answer has helped you.

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3 years ago

I will give brainliest to whoever can answer this question. It’s due in 40 min Please help me )):

Aleonysh [2.5K]

Given:

$m\angle L=m\angle Z=70^\circ$

$m\angle N=m\angle Y=90^\circ$

To find:

The value of $m\angle 1$ .

Solution:

In triangle XYZ,

$m\angle Y=m\angle N=90^\circ$ (Given)

$m\angle Z=m\angle L=70^\circ$ (Given)

$m\angle X+m\angle Y+m\angle Z=180^\circ$ [Angle sum property]

$m\angle 1+90^\circ+70^\circ=180^\circ$

$m\angle 1+160^\circ=180^\circ$

$m\angle 1=180^\circ-160^\circ$

$m\angle 1=20^\circ$

Therefore, the $m\angle 1$ is 20°.

5 0

3 years ago

an old book listed that $72$ turkeys were bought for $\$\square.\square\square$ each, at a total cost of $\$\square 67.9\square.

Westkost [7]

The cost of each turkey, if each is a smudge that represents some unreadable digit is $0.94

<h3>Cost of each turkey</h3><h3 />

Total number of turkey bought = 72
Total cost = $67.9

Cost of each turkey = Total cost / Total number of turkey bought

= 67.9 / 72

= 0.943055555555555

Approximately,

Cost of each turkey = $0.94

Therefore, the cost of each turkey, if each is a smudge that represents some unreadable digit is $0.94

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1 year ago

A shipment of 11 printers contains 2 that are defective. Find the probability that a sample of size 2, drawn from the 11, will

svet-max [94.6K]

The required probability is $\frac{36}{55}$

<u>Solution:</u>

Given, a shipment of 11 printers contains 2 that are defective.

We have to find the probability that a sample of size 2, drawn from the 11, will not contain a defective printer.

Now, we know that, $\text { probability }=\frac{\text { favourable outcomes }}{\text { total outcomes }}$

Probability for first draw to be non-defective $=\frac{11-2}{11}=\frac{9}{11}$

(total printers = 11; total defective printers = 2)

Probability for second draw to be non defective $=\frac{10-2}{10}=\frac{8}{10}=\frac{4}{5}$

(printers after first slot = 10; total defective printers = 2)

Then, total probability $=\frac{9}{11} \times \frac{4}{5}=\frac{36}{55}$

7 0

3 years ago

Help please photo is above

Zina [86]

Answer:

y = 5

x = 10

Step-by-step explanation:

-4(2y) + 11y

-8y + 11y = 15

3y = 15

/ 3 /3

y = 5

x = 10

3 0

2 years ago