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rosijanka [135]
3 years ago
9

When are x+3 and 2x equal? When are they not equal?

Mathematics
1 answer:
irinina [24]3 years ago
3 0

Answer:

x+3= 2x when x = 3

3+3 = 2*3

6= 6

They are not equal when x is any other number rather than 3

You might be interested in
1.) -2(6 - 2x) = 4(-3 + x)<br> 2.) 5 - 1(2x + 3) = -2(4 + x)
Scrat [10]

Let's solve your equation step-by-step.

Question 1:   −2(6−2x) =4(−3+x)

 

Step 1: Simplify both sides of the equation.

−2(6−2x) =4(−3+x)

(−2) (6) +(−2) (−2x) =(4)(−3)+(4)(x)(Distribute)

−12+4x=−12+4x

4x−12=4x−12

 

Step 2: Subtract 4x from both sides.

4x−12−4x=4x−12−4x

−12=−12

 

Step 3: Add 12 to both sides.

−12+12=−12+12

0=0

Answer: All real numbers are solutions.

Question 2:  

Let's solve your equation step-by-step.

5−1(2x+3) =−2(4+x)

 

Step 1: Simplify both sides of the equation.

5−1(2x+3) =−2(4+x)

5+(−1) (2x) +(−1) (3) =(−2) (4)+(−2)(x)(Distribute)

5+−2x+−3=−8+−2x

(−2x) +(5+−3) =−2x−8(Combine Like Terms)

−2x+2=−2x−8

−2x+2=−2x−8

 

Step 2: Add 2x to both sides.

−2x+2+2x=−2x−8+2x

2=−8

 

Step 3: Subtract 2 from both sides.

2−2=−8−2

0=−10

 

Answer: There are no solutions.

 

8 0
3 years ago
If <img src="https://tex.z-dn.net/?f=%20x%20%3D%20%5Cfrac%7B2y%7D%7Ba%7D%20" id="TexFormula1" title=" x = \frac{2y}{a} " alt=" x
inessss [21]

\bf A) \\\\\\ \cfrac{3\left( \frac{2y}{a} \right)}{y}\implies \cfrac{\frac{6y}{a}}{y}\implies \cfrac{6y}{a}\cdot \cfrac{1}{y}\implies \cfrac{6}{a}\quad \otimes \\\\\\ B) \\\\\\ \cfrac{6\left( \frac{2y}{a} \right)}{y}\implies\cfrac{\frac{12y}{a}}{y}\implies \cfrac{12y}{a}\cdot \cfrac{1}{y}\implies \cfrac{12}{a}\quad \otimes \\\\\\ C) \\\\\\ \cfrac{6y}{\left( \frac{2y}{a} \right)}\implies \cfrac{6y}{1}\cdot \cfrac{a}{2y}\implies 3a\quad \otimes

\bf D) \\\\\\ \cfrac{12\left( \frac{2y}{a} \right)}{y}\implies \cfrac{\frac{24y}{a}}{y}\implies \cfrac{24y}{a}\cdot \cfrac{1}{y}\implies \cfrac{24}{a}\quad \otimes \\\\\\ E) \\\\\\ \cfrac{12y}{\left( \frac{2y}{a} \right)}\implies \cfrac{12y}{1}\cdot \cfrac{a}{2y}\implies 6a\quad \checkmark

4 0
4 years ago
Answer these 5 question and you can have 35 points
Tems11 [23]

Answer:

Step-by-step explanation:

1: no

2: no

3: Mario Kart (duh)

4: Netflix of XOD

5: I dont know. There are many reasons he should but many reasons he shouldn't.

7 0
3 years ago
Read 2 more answers
Solve for x. 3x−1=9x+2 Enter your answer in the box. x =
julia-pushkina [17]

Answer:

x= -1

Step-by-step explanation:

3x-1=2x2 (calculate the product)

3x-1=4x (move terms)

3 x - 4 x =1 (collect the terms)

- x = 1 (change the signs)

Solution is x = -1

3 0
3 years ago
Read 2 more answers
Divide -3x^3-2x^2-x-2 by x-2
Rasek [7]

Let's do this by Briot-Ruffini


First: Find the monomial root


x - 2 = 0

x = 2


Second: Allign this root with all the other coeficients from equation

Equation = -3x³ - 2x² - x - 2

Coeficients = -3, -2, -1, -2

2 | -3 -2 -1 -2


Copy the first coeficient


2 | -3 -2 -1 -2

-3


Multiply him by the root and sum with the next coeficient


2.(-3) = -6

-6 + (-2) = -8


2 | -3 -2 -1 -2

-3 -8


Do the same


2.(-8) = -16

-16 + (-1) = -17


2 | -3 -2 -1 -2

-3 -8 -17


The same,


2.(-17) = -34

-34 + (-2) = -36


2 | -3 -2 -1 -2

-3 -8 -17 -36


Now you just need to put the "x" after all these numbers with one exponent less, see


2 | -3x³ - 2x² - 1x - 2

-3x² - 8x - 17 -36


You may be asking what exponent -36 should be, and I say:


None or the monomial. He's like the rest of this division, so you can say:


(-3x³ - 2x² - x - 2)/(x - 2) = -3x² - 8x - 17 with rest -36 or you can say:

(-3x³ - 2x² - x - 2)/(x - 2) = -3x² - 8x - 17 - 36/(x - 2)


Just divide the rest by the monomial.

5 0
3 years ago
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