Answer:
of their corresponding sides.
A=2<span>πr(r+h)
</span>80π=<span>2π(5)(5+h)
</span>80π=10π(5+h)
80π=50π + 10πh
30π=10πh
3=h
Answer: The sailboat is at a distance of 15 km from the port.
Step-by-step explanation: Given that a sail boat leaves port and sails 12 kilometers west and then 9 kilometers north.
We are to find the distance between the sailboat from the port in kilometers.
Since the directions west and north are at right-angles, we can visualize the movement of the sailboat in the form of a right-angled triangle as shown in the attached figure.
The sailboat moves leaves the port at P and reach O after sailing 12 km west. From point O, again it moves towards north 9 km and reach the point S.
PS = ?
Using the Pythagoras theorem, we have from right-angled triangle SOP,
Thus, the sailboat is at a distance of 15 km from the port.
Answer:
4.2 cm
Step-by-step explanation:
The law of cosines is applicable.
l² = k² +m² -2km·cos(L)
l² = 5.1² +1.2² -2·5.1·1.2·cos(35°) ≈ 17.4236
l ≈ √17.4236
l ≈ 4.2 . . . cm
Answer:
Square
Explanation:
A square is the only other shape with 4 right angles