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den301095 [7]
4 years ago
15

How many milliliters of .5 M HCl will neutralize 35 mL of 1 M NaOH?

Chemistry
1 answer:
wel4 years ago
4 0
I believe the answer would be c because more hcl wouldnt make it more concentrated (increase moles) so there shouldnt be a need for any extra
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Plastic is used for making a large variety of articles of daily use and these articles are very attractive. But it is advised to
boyakko [2]

Answer:

please select my answer as brainlist answers

Explanation:

plastic is harmful for the environment

4 0
3 years ago
Read 2 more answers
Write balanced ionic equations and net ionic equations for the following reactions.
Kipish [7]
The ionic equation will be: 
<span>Mg2+(aq) + 2OH-(aq) + 2H+(aq) + 2NO3-(aq) → Mg2+(aq) + 2NO3-(aq) + 2H2O(l) 
</span>And the net ionic: 
<span>2OH-(aq) + 2H+(aq) → 2H2O(l) 
</span>a Balanced equation would be:
<span>Mg(OH)2(aq) + 2HNO3(aq) → Mg(NO3)2 (aq) + 2H2O(l) 
</span>Now  thsi si so because of the standard equation which is base plus acid=Salt plus water. We need to have in mindo that Mg(OH)2 is sparingly soluble in water and is aqueous mos of the times
7 0
3 years ago
Which molecule has polar bonding and is nonpolar? A. H2O B. BF3 C. NH3 D. NCl3 E. CH2Cl2
Marina CMI [18]

Answer:

B. BF₃

Explanation:

All the molecules have polar bonds, but a molecule will be nonpolar if the molecule has the symmetry that makes the bond dipoles cancel.

To make the decision, we must

  1. Draw the Lewis structure
  2. Assign the VSEPR electron geometry
  3. Determine the molecular shape.
  4. Examine the symmetry of the molecule

===============

<em>A. Water </em>

Lewis structure = H-O-H (2 bonding pairs, 2 lone pairs)

Electron geometry = AX₂E₂ tetrahedral

Molecular geometry = bent

Symmetry (see Figure A): The two O-H bonds are polar, with their negative ends pointing towards the O. The horizontal components of the bond dipoles cancel, but the vertical components reinforce each other and give an upward pointing molecular dipole. This is a <em>polar molecule with polar bonds</em>.

===============

<em>B. Boron trifluoride </em>

Lewis structure = BF₃ (3 bonding pairs)

Electron geometry = AX₃, trigonal planar

Molecular geometry = trigonal planar

Symmetry (see Figure B): The three B-F bonds are polar, with their negative ends pointing towards the F. The horizontal components of the bond dipoles cancel, but the vertical components of the two downward -pointing dipoles reinforce each other and give a resultant that is equal and opposite to the upward dipole. Thus, the bond dipoles cancel. This is a nonpolar molecule with polar bonds.

===============

<em>C. Ammonia</em>

Lewis structure = :NH₃ (3 bonding pairs, 1 lone pairs)

Electron geometry = AX₃E, tetrahedral

Molecular geometry = trigonal pyramidal

Symmetry (see Figure C): The three N-H bonds are polar, with their negative ends pointing towards the N. The horizontal components of the bond dipoles cancel, but the vertical components reinforce each other and give an upward pointing molecular dipole. This is a <em>polar molecule with polar bonds</em>.

===============

<em>D. Nitrogen trichloride </em>

Lewis structure = :NCl₃ (3 bonding pairs, 1 lone pair)

Electron geometry = AX₃E, tetrahedral

Molecular geometry = trigonal pyramidal

Symmetry (see Figure D): The three N-Cl bonds are polar, with their negative ends pointing towards the Cl. The horizontal components of the bond dipoles cancel, but the vertical components reinforce each other and give a downward pointing molecular dipole. This is a <em>polar molecule with polar bonds</em>.

===============

<em>E. Dichloromethane </em>

Lewis structure = H₂CCl₂ (4 bonding pairs)

Electron geometry = AX₄, tetrahedral

Molecular geometry = tetrahedral

Symmetry (see Figure E): The two C-H bonds are nonpolar, but the two C-Cl bonds are polar with their negative ends pointing towards the Cl. The horizontal components of the bond dipoles cancel, but the vertical components reinforce each other and give a downward pointing molecular dipole. This is a <em>polar molecule with polar bonds</em>.

3 0
3 years ago
WHICH IS WHICH?
Aleksandr-060686 [28]

Answer:

- First: element.

- Second: Compound.

- Third: element.

- Fourth: Compound.

Explanation:

Hello.

In this case, since elements are composed the same atom and compounds are composed by two different atoms, we can see that:

- First: it is an element as each sphere seems to be the same.

- Second: It is a compound as two different type of spheres are shown, white and black, considering each sphere is a different element.

- Third: it is an element because the spheres are equal, in fact, it is a diatomic element as two atoms are joined per molecule.

- Fourth: It is a compound as well since each molecule has two colored spheres and one white sphere, meaning that it has two different atoms per molecule.

Best regards.!

8 0
4 years ago
100 Points.
hodyreva [135]
I think it’s C but I’m not sure
6 0
3 years ago
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