Oil spills are a very serious form of pollution. They severely affect marine biodiversity and coastal ecosystems. The table show
s methods that can be used to control oil spills.
A scientist wants to design a solution to control an oil spill. This solution should decrease the impact of the oil spill on the local biodiversity of the ecosystem. The solution should also be quick and effective but have minimal negative effects on the environment. Which of the following solutions would be best for the scientist to choose?
A. allowing natural processes to occur without any human intervention
B. using mechanical methods to collect the oil in one part of the ecosystem
C. using chemical methods to break the oil into smaller droplets
D. using bioremediation to speed up existing, natural oil degradation
Hellpppp!
A scientist wants to design a solution to control an oil spill. This solution should decrease the impact of the oil spill on the local biodiversity of the ecosystem. The solution should also be quick and effective but have minimal negative effects on the environment. Which of the following solutions would be best for the scientist to choose?
A. allowing natural processes to occur without any human intervention
B. using mechanical methods to collect the oil in one part of the ecosystem
C. using chemical methods to break the oil into smaller droplets
D. using bioremediation to speed up existing, natural oil degradation
Hellpppp!
2 answers:
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Answer:
Explanation:
From the information given:
Mass of carbon tetrachloride = 5 kg
Pressure = 1 bar
The given density for carbon tetrachloride = 1590 kg/m³
The specific heat of carbon tetrachloride = 0.84 kJ/kg K
From the composition, the initial volume of carbon tetrachloride will be:
= 0.0031 m³
Suppose is independent of temperature while pressure is constant;
Then:
The change in volume can be expressed as:
However; the workdone = -PdV
W = - 7.6 J
The heat energy Q = Δ h
Q = 84 kJ
The internal energy is calculated by using the 1st law of thermodynamics; which can be expressed as;
ΔU = ΔQ + W
ΔU = 84 kJ + ( -7.6 × 10⁻³ kJ)
ΔU = 83.992 kJ