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Basile [38]
2 years ago
6

Oil spills are a very serious form of pollution. They severely affect marine biodiversity and coastal ecosystems. The table show

s methods that can be used to control oil spills.
A scientist wants to design a solution to control an oil spill. This solution should decrease the impact of the oil spill on the local biodiversity of the ecosystem. The solution should also be quick and effective but have minimal negative effects on the environment. Which of the following solutions would be best for the scientist to choose?

A. allowing natural processes to occur without any human intervention
B. using mechanical methods to collect the oil in one part of the ecosystem
C. using chemical methods to break the oil into smaller droplets
D. using bioremediation to speed up existing, natural oil degradation

Hellpppp!

Chemistry
2 answers:
sesenic [268]2 years ago
5 0

Explanation:

The correct answer is option D

Viefleur [7K]2 years ago
4 0

Answer:

D. using bioremediation to speed up existing, natural oil degradation.

Explanation:

Got an A on this.

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At 25.0°c, a solution has a concentration of 3.179 m and a density of 1.260 g/ml. the density of the solution at 50.0°c is 1.249
oksano4ka [1.4K]

Answer: -

3.151 M

Explanation: -

Let the volume of the solution be 1000 mL.

At 25.0 °C, Density = 1.260 g/ mL

Mass of the solution = Density x volume

= 1.260 g / mL x 1000 mL

= 1260 g

At 25.0 °C, the molarity = 3.179 M

Number of moles present per 1000 mL = 3.179 mol

Strength of the solution in g / mol

= 1260 g / 3.179 mol = 396.35 g / mol (at 25.0 °C)

Now at 50.0 °C

The density is 1.249 g/ mL

Mass of the solution = density x volume = 1.249 g / mL x 1000 mL

= 1249 g.

Number of moles present in 1249 g = Mass of the solution / Strength in g /mol

= \frac{1249 g}{396.35 g/mol}

= 3.151 moles.

So 3.151 moles is present in 1000 mL at 50.0 °C

Molarity at 50.0 °C = 3.151 M

7 0
3 years ago
An astronomer observes an asteroid in the solar system. He notes that the asteroid is three times farther from the Sun than Eart
ozzi

Answer:

3 AU

Explanation:

The distance from the Earth to the Sun is known as 1 AU, or 1 Astronomical Unit. If an asteroid is three times this distance, it is 3 AU away.

7 0
3 years ago
For the reaction below, complete the rate expression that relates the change in concentration with respect to time to the rate o
Ann [662]

Answer: Rate in terms of disappearance of NO = -\frac{1d[NO]}{2dt}

Rate in terms of disappearance of Cl_2= -\frac{1d[Cl_2]}{1dt}

Rate in terms of appearance of NOCl = \frac{1d[NOCl]}{2dt}

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

2NO+Cl_2\rightarrow 2NOCl

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.

Rate in terms of disappearance of  = -\frac{1d[NO]}{2dt}

Rate in terms of disappearance of = -\frac{1d[Cl_2]}{1dt}

Rate in terms of appearance of NOCl = +\frac{1d[NOCl]}{2dt}

5 0
3 years ago
1362205.2 in scientific notation
SVETLANKA909090 [29]
1.3622052x10^6 you move the . 6 places to the left making it a positive 10^6
8 0
3 years ago
Calculate the pH of a solution that is 0.210 M in nitrous acid (HNO2) and 0.290 M in potassium nitrite (KNO2). The acid dissocia
jeka94

Answer:

pH = 3.49

Explanation:

We have a buffer system formed by a weak acid (HNO₂) and its conjugate base (NO₂⁻ coming from KNO₂). We can calculate the pH  of a buffer ssytem using the Henderson-Hasselbach equation.

pH = pKa + log [base] / [acid]

pH = -log Ka + log [NO₂⁻] / [HNO₂]

pH = -log 4.50 × 10⁻⁴ + log 0.290 M / 0.210 M

pH = 3.49

6 0
3 years ago
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