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Basile [38]
1 year ago
6

Oil spills are a very serious form of pollution. They severely affect marine biodiversity and coastal ecosystems. The table show

s methods that can be used to control oil spills.
A scientist wants to design a solution to control an oil spill. This solution should decrease the impact of the oil spill on the local biodiversity of the ecosystem. The solution should also be quick and effective but have minimal negative effects on the environment. Which of the following solutions would be best for the scientist to choose?

A. allowing natural processes to occur without any human intervention
B. using mechanical methods to collect the oil in one part of the ecosystem
C. using chemical methods to break the oil into smaller droplets
D. using bioremediation to speed up existing, natural oil degradation

Hellpppp!

Chemistry
2 answers:
sesenic [268]1 year ago
5 0

Explanation:

The correct answer is option D

Viefleur [7K]1 year ago
4 0

Answer:

D. using bioremediation to speed up existing, natural oil degradation.

Explanation:

Got an A on this.

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A volume of 80.0 mL of H2O is initially at room temperature (22.00 ∘C). A chilled steel rod at 2.00 ∘C is placed in the water. I
murzikaleks [220]

Answer:

The mass of the steel bar is 26.833 grams

Explanation:

<u>Step 1: </u>data given

ΣQ gained = ΣQ lost

Q=m*C*ΔT

with m = mass in grams

with C= specific heat capacity ( in J/(g°C))

with ΔT = change in temperature = T2-T1

Qsteel = Qwater

msteel * Csteel * (T2steel - T1steel) = mwater * Cwater * (T2water - T1water)

Mass of steel = TO BE  DETERMINED

mass of water =⇒ since 1mL = 1g : 80 mL = 80g

Csteel =0.452 J/(g °C

Cwater = 4.18 J/(g °C

initial temperature steel T1 : 2 °C

final temperature steel T2 = 21.3 °C

initial temperature water T1 =22 °C

final temperature water T2 = 21.3 °C

<u>Step 2:</u> Calculate mass of steel

msteel * Csteel * (T2steel - T1steel) = mwater * Cwater * (T2water - T1water)

msteel * 0.452 *(21.3-2) = 80 * 4.18 * (21.3-22)

msteel = (80 * 4.18 * (-0.7)) / (0.452 * 19.3)

msteel = -234.08 / 8.7236

msteel = -26.833 g

Since mass can't be negative we should take the absolute value of it = 26.833g

The mass of the steel bar is 26.833 grams

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