I think the correct answer would be the second option. The volume of 1 mol of gas at standard temperature and pressure would be the same for any gas. If and only if the gas is an ideal gas. This is according to the ideal gas law ( PV = nRT ), at STP ( P = 1 atm T = 273.15 K ) you would calculate the volume of the gas to be 22.4 L. So, 1 mol of any ideal gas would occupy 22.4 L of volume. We calculate as follows:
PV = nRT
V = nRT / P
V = (1 mol ) (0.08205 L-atm / mol K) (273.15 K ) / 1 atm
V = 22.4 L <span />
Basically since i have to put at least 20 characthers I'm gonna ramble then give the answer so here ya go: Its C :)
Answer:
the oxidation number of hydrogen is +2, while oxygen is -2
Hey there!
Atomic mass Bromine ( Br ) = 79.9 u
Therefore:
79.9 g Br --------------- 22.4 L ( at STP )
18.0 g Br --------------- volume ??
Volume Br = 18.0 * 22.4 / 79.9
Volume Br = 403.2 / 79.9
Volume Br = 5.046 L
hope this helps!