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tangare [24]
3 years ago
14

Alexandra's gross annual salary is $38,556. What is the maximum amount of rent she can afford to pay? Round your answer to the n

earest dollar.
A. $900
B. $1220
C. $1324
D. $1607
Mathematics
1 answer:
Darya [45]3 years ago
3 0

Answer:

A.$900

Step-by-step explanation:

To find how much Alexandra can afford to pay for monthly rent, we first need to find her monthly income.

Monthly Income = $38,556/12

Monthly Income = $3,213

Now since we have the 28/36 rule where a household should only spend a maximum amount of 28% of the gross monthly income we need to multiply the monthly income by 0.28.

Monthly Rent = $3,213 * 0.28

Monthly Rent = $899.64 or $900

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Mr Jansen budget is $400 for clothes. if he buys a new suit for 290$ and a tie for $35 how many shirts can he buy at 20$ each. ​
Evgen [1.6K]

Answer:

the answer is 3

5 0
4 years ago
Read 2 more answers
A lab technician shows up to the lab at 9am on Monday and finds a culture of bacteria x containing 5328 bacteria. Each culture s
zubka84 [21]

Answer:

9 pm on a Sunday, 55 .5 days before

Step-by-step explanation:

if there were 6 bacteria initially and from the growth rate we noticed that it doubled every 3 hours

because by 9 am Monday morning there were 5328 bacteria and then by 12 noon (3 hours later), there were 10, 656 bacteria

what we need to know is how long did it take 6 bacteria to become 5328

so

if 6 bacteria = 1 hour

12 bacteria = 3 hours

24 bacteria = 6 hours

then

5328 bacteria = x hours

taking the ratio

\frac{5328}{24} =\frac{x}{6}\\ \\222=\frac{x}{6} \\\\\\222(6) = x\\\\1332=x

we need to now convert this into hours

so we divide by 24

\frac{1332}{24} =55.5

so

9 am 55.5 days before should fall on a Sunday

4 0
3 years ago
Find the number c that satisfies the conclusion of the Mean Value Theorem on the given interval. (Enter your answers as a comma-
ivanzaharov [21]

Answer:

c = \displaystyle\frac{9}{4}

Step-by-step explanation:

The following information is missing in the given question:

f(x) = \sqrt{x}

Using this we may solve the question as:

We are given the following in the question:

f(x) = \sqrt{x}, x \in [0,9]

We have to find the number c such that f(x) satisfies the Mean value theorem.

Mean Value theorem:

It states that if the function is differentiable in the closed interval [a,b], differentiable in the interval (a,b), then there exist c in (a,b) such that:

f'(c) = \displaystyle\frac{f(b)-f(a)}{b-a}

Now,

f(x) = \sqrt{x}\\f'(x) = \frac{1}{2\sqrt{x}}

Continuity in [0,9]

Since a polynomial function is continuous everywhere, f(x) is continuous in [0,9]

Differentiability in (0,9)

Since a polynomial function is differentiable everywhere the given function is differentiable in interval (0,9)

Then, by mean value theorem:

f'(c) = \displaystyle\frac{f(b)-f(a)}{b-a}\\\\\frac{1}{2\sqrt{c}} = \frac{f(9) - f(0)}{9-0} = \frac{3}{9}\\\\\frac{1}{2\sqrt{c}} = \frac{1}{3}\\\\c= \frac{9}{4}

7 0
3 years ago
Order the numbers from least to greatest <br><br> -1,4 -8/5 0.6 -0.9 1/4
MrRa [10]
1/4  0.6  0.9  1  8/5  4  Hope this helps.
3 0
3 years ago
Read 2 more answers
Solve for m : (-m)= 37
77julia77 [94]
It should be -37. i hope this helps :)
7 0
3 years ago
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