Quick math, please help! What is the length of side BC in the triangle? Thank you!

Mathematics

1 answer:

antiseptic1488 [7]3 years ago

3 0

Answer:

I got 24 for the answer!

Step-by-step explanation:

x+8=2x-1

solve for x, and you will get x=9

then you will plug this into bc, 3x-3, and that will be 3(9)-3, and you will get 24! Hope this is right!

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Find the tangent of ∠I.

Nady [450]

Answer:

tanI = $\frac{\sqrt{70} }{5}$

Step-by-step explanation:

We require to calculate GH using Pythagoras' identity in the right triangle.

GH² + GI² = HI²

GH² + 5² = ( $\sqrt{95}$ )²

GH² + 25 = 95 ( subtract 25 from both sides )

GH² = 70 ( take square root of both sides )

GH = $\sqrt{70}$

Then

tanI = $\frac{opposite}{adjacent}$ = $\frac{GH}{GI}$ = $\frac{\sqrt{70} }{5}$

4 0

3 years ago

Help with this question ASAP!!!

Wewaii [24]

Answer:

$\large\boxed{D\left(0,\ -\dfrac{20}{3}\right),\ \dfrac{2}{3}}$

Step-by-step explanation:

$\triangle FOD\sim\triangle HOG,\ \text{therefore the sides are in proportion:}\\\\\dfrac{OF}{OD}=\dfrac{OH}{OG}\\\\\text{We have}\\\\OF=4,\ \ OH=6,\ OG=10\\\\\text{Substitute:}\\\\\dfrac{4}{OD}=\dfrac{6}{10}\qquad\text{cross multiply}\\\\6OD=(4)(10)\\\\6OD=40\qquad\text{divide both sides by 6}\\\\OD=\dfrac{40}{6}\\\\OD=\dfrac{20}{3}\\\\\text{Therefore}\ D\left(0,\ -\dfrac{20}{3}\right).\\\\\text{The scale factor:}\ \dfrac{OF}{OH}=\dfrac{4}{6}=\dfrac{2}{3}$