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dimulka [17.4K]

4 years ago

10

PLEASE HELPME!!BRAINLIEST!! The development of new technology requires the evaluation of the overall benefit to cost ratio of th

e new technology.
Which factor would least likely be used in a benefit-cost analysis of electric vehicles (EVs) when comparing to traditional internal combustion vehicles?
A) fuel cost
B) emissions
C) fuel economy
D) ride comfort

2 answers:

Jlenok [28]4 years ago

6 0

I think the answer is D, ride comfort. This is something that doesn't necessarily change between EVs and internal combustion vehicles, but is more up to the company itself and I don't think it would really be considered a benefit nor do anything for the environment

Alborosie4 years ago

5 0

D ride comfort ps is that u Jason

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Distance in scientific notation

n200080 [17]

Answer:

(See explanation for further information)

Explanation:

a) The distances of each planet with respect to the Sun is:

Mercury - $57.909 \times 10^{6}\,mi$

Venus - $67.240\times 10^{6}\,mi$

Earth - $92.960\times 10^{6}\,mi$

Mars - $141.600\times 10^{6}\,mi$

Jupiter - $483.800\times 10^{6}\,mi$

Saturn - $888.200\times 10^{6}\,mi$

Uranus - $1,787\times 10^{6}\,mi$

Neptune - $2,795\times 10^{6}\,mi$

b) The solutions are presented below:

A. The distance between Venus and Jupiter is:

$\Delta s = 483.800\times 10^{6}\,mi-67.240\times 10^{6}\,mi$

$\Delta s = 416.560\times 10^{6}\,mi$

B. The combined distance from the Sun is:

$\Delta s = 57.909\times 10^{6}\,mi + 67.240\times 10^{6}\,mi +92.960\times 10^{6}\,mi$

$\Delta s = 218.109\times 10^{6}\,mi$

Which is less than the distance from the Sun to Neptune ( $2,795\times 10^{6}\,mi$ ).

C. The new distance of Earth is $929.60 \times 10^{6}\,mi$ ( $929,600,000\,mi$ ). Saturn would be the closest planet to Earth, whose distance:

Scientific notation:

$\Delta s = 929.600\times 10^{6}\,mi-888.200\,\times 10^{6}\,mi$

$\Delta s = 41.4\times 10^{6}\,mi$

Standard notation:

$\Delta s = 929,600,000\,mi - 888,200,000\,mi$

$\Delta s = 41,400.000\,mi$

3 0

4 years ago

On one of the shelves in your physics lab is displayed an antique telescope. A sign underneath the instrument says that the tele

Vesna [10]

Answer:

The focal length fe of the eyepiece is <em>2.86 cm</em>

Explanation:

Since we are given the telescope's magnification and the length of the tube, we can use the expressions

<em>M = f_o/fe (1)</em> and

<em>l = f_o + fe (2)</em>

where

M is the telescope's magnification
l is the length of the tube
fe is the focal length of the eye-piece

Rearranging equation (2) to make f_o the subject of the formula, we get

<em>f_o = l - fe</em>

Substituting the above equation into equation (1) we get

<em>M = (l - fe)/fe ⇒ fe = l/(M +1)</em>

<em> ⇒ fe = 60/(20 + 1)</em>

⇒ <em>fe = 2.86 cm</em>

4 0

4 years ago

An airplane maintains a speed of 627 km/h relative to the air it is flying through as it makes a trip to a city 787 km away to t

amid [387]

Answer:1.33 hr

Explanation:

Given

Speed of airplane relative to air=627 km/h

Distance traveled =787 km

Speed of wind=38.4 km/h

Wind is blowing in opposite direction therefore net speed is

$v_{net}=627-38.4=588.6 km/h$

thus time taken is

$t=\frac{distance}{speed}$

$t=\frac{787}{588.6}=1.33 hr$

4 0

4 years ago

Pand S waves are both

leva [86]

Answer:

3.body

Explanation:

Both P and S waves are both body waves. Body waves are waves that travels through the earth.

P and S waves are elastic seismic waves that moves within the earth. Love and Rayleigh waves are surface waves that travels through the surface.

P waves is also known as primary waves
S waves are known secondary waves.

These waves are the first set of waves to arrive a seismic station before the surface waves are picked up.

3 0

3 years ago

A 2200 kg SUV traveling at 23.9 m/s can be stopped in 0.16 s if it hits a concrete wall. Assume that a 60 kg person was in the c

Jlenok [28]

Answer:

8962.5 N

Explanation:

From fundamental kinematics equations, acceleration, a is given by $a=\frac {v-u}{t}$ where v is final velocity, u is initial velocity and t is time

We also know that force is a product of mass and acceleration of an object and substituting $a=\frac {v-u}{t}$ in the formula F=ma we obtain

$F=ma=m\frac {v-u}{t}$ where m is the mass of the body

$F=60\times\frac {0-23.9}{0.16}=-8962.5 N$

Therefore, the force is 8962.5 N

4 0

4 years ago