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dimulka [17.4K]

4 years ago

10

PLEASE HELPME!!BRAINLIEST!! The development of new technology requires the evaluation of the overall benefit to cost ratio of th

e new technology.
Which factor would least likely be used in a benefit-cost analysis of electric vehicles (EVs) when comparing to traditional internal combustion vehicles?
A) fuel cost
B) emissions
C) fuel economy
D) ride comfort

2 answers:

Jlenok [28]4 years ago

6 0

I think the answer is D, ride comfort. This is something that doesn't necessarily change between EVs and internal combustion vehicles, but is more up to the company itself and I don't think it would really be considered a benefit nor do anything for the environment

Alborosie4 years ago

5 0

D ride comfort ps is that u Jason

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You nose out another runner to win the 100.000m dash. If your total time for the race was 11.8 seconds and you aced out the othe

daser333 [38]

You completed 100.000 m in 11.800 second

you aced out the other runner by 0.001 seconds

time taken by other runner to finish = 11.800 + 0.001 = 11.801s

speed of other runner = 100/11.801 m/s

distance covered by him in 11.8 s = 100/11.801 × 11.8 = 99.992 m

you won by = 100 - 99.992 = 0.008 meter

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4 years ago

What is the magnitude (in N/C) and direction of an electric field that exerts a 4.00 x 10^−5 N upward force on a −2.00 µC charge

emmasim [6.3K]

Answer:

The magnitude of electric field is $1.25\times10^{14}\ N/C$ in downward.

Explanation:

Given that,

Force $F= 4.00\times10^{-5}\ N$

Charge q= -2.00 μC

We know that,

Charge is negative, then the electric field in the opposite direction of the exerted force.

We need to calculate the magnitude of electric field

Using formula of electric force

$F = qE$

$E = \dfrac{F}{q}$

$E=\dfrac{4.00\times10^{-5}}{-2.00\times1.6\times10^{-19}}$

$E=-1.25\times10^{14}\ N/C$

Negative sign shows the opposite direction of electric force.

Hence, The magnitude of electric field is $1.25\times10^{14}\ N/C$ in downward.

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4 years ago

70 POINTS!!!! PLZ ANSWER!!!!! The Newton-Clark moraine is located on the volcano Mount Hood. It contains approximately 950 milli

Strike441 [17]

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8 0

4 years ago

Read 2 more answers

2. A small piece of dust is located in between two oppositely charged parallel plates where there exists a uniform electric fiel

Alla [95]

Answer:

a

The total charge is $q = 1.6*10^{-4}C$

b

The change in potential energy is $\Delta U = -4*10^{-2}J$

c

The height is $h= 8.2cm$

Explanation:

From the question we are told that the

The magnitude of electric field is $E = 5000N/C$

The number of proton is $N_p = 1*10^{15}$

The distance between the plates is $d = 5cm = \frac{5}{100} = 0.05m$

The total charge can be mathematically represented as

$q = N_p * e$

Where e is the charge on one proton which has a value of $=1.6*10^{-19}C$

Substituting values

$q = 1 *10^{15} * 1.6*10^{-19} = 1.6 *10^{-4}C$

The change in potential energy is mathematically represented ads

$\Delta U = -(qE)d$

where the negative sign shows that the work done by the electric force is against the electric field

Substituting values

$\Delta U = - 1.6*10^{-4} * 5000 * 0.05$

$= -4*10^{-2}J$

The mass of the bead is given as 0.05kg

The change in potential due to gravity is mathematically given as

$\Delta U = -mgh$

the negative sign is due to the fact that the height is decreasing

And $g =9.8m/s^2$

Making h the subject

$h = \frac{\Delta U}{mg}$

Substituting values

$h = \frac{4*10^{-2}}{0.05 * 9.8}$

$=0.081m = 0.082 *100 = 8.2cm$

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4 years ago

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Andrew [12]

can u translate pls

Explanation:

5 0

3 years ago