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djyliett [7]
3 years ago
15

Pand S waves are both

Physics
1 answer:
leva [86]3 years ago
3 0

Answer:

3.body

Explanation:

Both P and S waves are both body waves. Body waves are waves that travels through the earth.

P and S waves are elastic seismic waves that moves within the earth. Love and Rayleigh waves are surface waves that travels through the surface.

  • P waves is also known as primary waves
  • S waves are known secondary waves.

These waves are the first set of waves to arrive a seismic station before the surface waves are picked up.

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An unconformity, or abnormality in the layers of rocks, signifies that the process of layering was somehow interrupted. The only feasible choice for this would be (B), where erosion would have interrupted the layering process.
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John argues that energy is not conserved because when someone presses the brakes in a moving car, kinetic energy is lost. What s
babunello [35]
kinetic energy is converted into elastic potential energy stored in the brakes.
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3 years ago
An oceanographer is studying how the ion concentration in seawater depends on depth. She makes a measurement by lowering into th
Black_prince [1.1K]

Answer:

a)  R = ρ₀ L /π(r_b² - R_a²) , b)  ρ₀ = V / I    π (r_b² - R_a²) / L

Explanation:

a) The resistance of a material is given by

          R = ρ l / A

where ρ is the resistivity, l is the length and A is the area

the length is l = L and the resistivity is ρ = ρ₀

the area is the area of ​​the cylindrical shell

           A = π r_b² - π r_a²

           A = π (r_b² - r_a²)

we substitute

         R = ρ₀ L /π(r_b² - R_a²)

b) The potential difference is related to current and resistance by ohm's law

         V = i R

         

we subsist the expression of resistance

          V = I ρ₀ L /π (r_b² - R_a²)

           ρ₀ = V / I    π (r_b² - R_a²) / L

6 0
3 years ago
A swing has a period of 10 seconds. What is its frequency ?
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Frequency = 1 / (period)

Frequency = 1 / (10 seconds) = (1/10) ( / second) = 0.1 per second = <em>0.1 Hz</em>.


4 0
3 years ago
Calculate the amount of heat liberated (in kj) from 411 g of mercury when it cools from 88.0°c to 12.0°c.
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You should note that the melting point of mercury is -38.83°C, while the boiling point is at 356.7°C. Then, that means that there is no latent heat involved here. We only compute for the sensible heat.

ΔH = mCpΔT
The Cp of mercury is 0.14 J/g·°C
Thus,
ΔH = (411 g)(0.14 J/g·°C)(88 - 12°C)
<em>ΔH = 4,373.04 J</em>
5 0
4 years ago
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