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Alex17521 [72]
4 years ago
5

A 2200 kg SUV traveling at 23.9 m/s can be stopped in 0.16 s if it hits a concrete wall. Assume that a 60 kg person was in the c

ar when it hir the wall. What is the average force exerted on the person
Physics
1 answer:
Jlenok [28]4 years ago
4 0

Answer:

8962.5 N

Explanation:

From fundamental kinematics equations, acceleration, a is given by a=\frac {v-u}{t} where v is final velocity, u is initial velocity and t is time

We also know that force is a product of mass and acceleration of an object and substituting a=\frac {v-u}{t}  in the formula F=ma we obtain

F=ma=m\frac {v-u}{t}  where m is the mass of the body

F=60\times\frac {0-23.9}{0.16}=-8962.5 N

Therefore, the force is 8962.5 N

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Approximately \rm 90\; kJ.

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There are two half-reactions in this question. \rm Cu^{2+} + 2\,e^{-} \rightleftharpoons Cu and \rm Pb^{2+} + 2\,e^{-} \rightleftharpoons Pb. Either could be the cathode (while the other acts as the anode.) However, for the reaction to be spontaneous, the value of E^{\circ}(\text{cell}) should be positive.

In this case, E^{\circ}(\text{cell}) is positive only if \rm Cu^{2+} + 2\,e^{-} \rightleftharpoons Cu is the reaction takes place at the cathode. The net reaction would be

\rm Cu^{2+} + Pb \to Cu + Pb^{2+}.

Its cell potential would be equal to 0.339 - (-0.130) = \rm 0.469\; V.

The maximum amount of electrical energy possible (under standard conditions) is equal to the free energy of this reaction:

\Delta G^{\circ} = n \cdot F \cdot E^{\circ} (\text{cell}),

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  • n is the number moles of electrons transferred for each mole of the reaction. In this case the value of n is 2 as in the half-reactions.
  • F is Faraday's Constant (approximately 96485.33212\; \rm C \cdot mol^{-1}.)

\begin{aligned}\Delta G^{\circ} &= n \cdot F \cdot E^{\circ} (\text{cell})\cr &= 2\times 96485.33212 \times (0.339 - (-0.130)) \cr &\approx 9.0 \times 10^{4} \; \rm J \cr &= 90\; \rm kJ\end{aligned}.

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