A 2200 kg SUV traveling at 23.9 m/s can be stopped in 0.16 s if it hits a concrete wall. Assume that a 60 kg person was in the c
1 answer:
Answer:
8962.5 N
Explanation:
From fundamental kinematics equations, acceleration, a is given by where v is final velocity, u is initial velocity and t is time
We also know that force is a product of mass and acceleration of an object and substituting in the formula F=ma we obtain
where m is the mass of the body
Therefore, the force is 8962.5 N
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Answer:
24 cm
Explanation:
Given:
Mass of proton = 1.67 × 10⁻²⁷ Kg
kinetic energy = 2.5 × 10⁻¹³ J
magnetic field in the cyclotron, B = 0.75 T
Now,
Kinetic energy = = 2.5 × 10⁻¹³ J
where, v is the velocity of the electron
or
= 2.5 × 10⁻¹³ J
or
v² = 2.99 × 10¹⁴
or
v = 1.73 × 10⁷ m/s
also,
centripetal force = magnetic force
or
= qvB
q is the charge of the electron
r is the radius of the dipole magnets
on substituting the respective values, we get
= 1.6 × 10⁻¹⁹ × 0.75
or
r = 0.2408 m ≈ 24 cm
Hence, the correct answer is 24 cm
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This is a problem of accelerated motion, where the acceleration involved is the gravitational acceleration:
, and where the negative sign means it points downwards, against the direction of the motion.
Therefore, we can use the following formula to solve the problem:
where
is the initial vertical velocity of the athlete, 
is the vertical velocity of the athlete at the maximum height (and 
at maximum height of an accelerated motion) and S is the distance covered between the initial and final moment (i.e., it is the maximum height). Re-arranging the equation, we get
This is a problem of accelerated motion, where the acceleration involved is the gravitational acceleration:
Therefore, we can use the following formula to solve the problem:
where
This question involves the concepts of Newton's Law of Gravitation and mass.
The force on Procyon A from Procyon B will be "equal" to the force on Procyon B from Procyon A, which has a value of "3.75 x 10²⁶ N".
Applying Newton's Law of Gravitation, we can find the force on Procyon A from Procyon B, which is equal to the force on Procyon B from Procyon A:
where,
F = force = ?
G = universal gravitational constant = 6.67 x 10⁻¹¹ N.m²/kg²
m₁ = mass of Procyon A = 3 x 10³⁰ kg
m₂ = mass of Procyon B = (2.5)(3 x 10³⁰ kg) = 7.5 x 10³⁰ kg
r = distance between them = 2 x 10¹² m
Therefore,
<u>F = 3.75 x 10²⁶ N</u>
Learn more about Newton's Law of Gravitation here:
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