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Alex17521 [72]
4 years ago
5

A 2200 kg SUV traveling at 23.9 m/s can be stopped in 0.16 s if it hits a concrete wall. Assume that a 60 kg person was in the c

ar when it hir the wall. What is the average force exerted on the person
Physics
1 answer:
Jlenok [28]4 years ago
4 0

Answer:

8962.5 N

Explanation:

From fundamental kinematics equations, acceleration, a is given by a=\frac {v-u}{t} where v is final velocity, u is initial velocity and t is time

We also know that force is a product of mass and acceleration of an object and substituting a=\frac {v-u}{t}  in the formula F=ma we obtain

F=ma=m\frac {v-u}{t}  where m is the mass of the body

F=60\times\frac {0-23.9}{0.16}=-8962.5 N

Therefore, the force is 8962.5 N

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A sample of radium-226 will decay to ¼ of its original amount after 3200 years. What is the half-life of radium-226?
lesantik [10]
<h3><u>Answer</u>;</h3>

1600 years

<h3><u>Explanation</u>;</h3>
  • Half life is the time taken for a radioactive isotope to decay by half of its original amount.
  • We can use the formula; N = O × (1/2)^n ; where N is the new mass, O is the original amount and n is the number of half lives.
  • A sample of radium-226 takes 3200 years to decay to 1/4 of its original amount.

Therefore;

<em>1/4 = 1 × (1/2)^n</em>

<em>1/4 = (1/2)^n </em>

<em>n = 2 </em>

Thus; <em>3200 years is equivalent to 2 half lives.</em>

<em>Hence, the half life of radium-226 is 1600 years</em>

3 0
3 years ago
A bullet glider and a target glider both have a mass of 0.200 kg. The bullet glider is moving 0.450 m/s
Romashka [77]

Answer:

the two gliders collide, the mobile glider will transfer a bit of time to the fixed glider, which is why it comes out with a speed that is smaller than that of the bullet glider.

Explanation:

When the two gliders collide, the mobile glider will transfer a bit of time to the fixed glider, which is why it comes out with a speed that is smaller than that of the bullet glider.

Changes can occur that the gliders unite and move with a cosecant speed less than the initial one.

The whole process must be analyzed using conservation of the moment.

             p₀ = m v₀

celestines que clash case

             p_f = (m + M) v

             po = pf

             m v₀ = (n + M) v

             v = \frac{m}{m+M}

calculemos

            v= \frac{0.200}{0.200+M} 0.450

            v= 0.09 m/s

elastic shock case

           p₀ = m v₀

           p_f = m v₁ +M v₂

           p₀ = p_f

           m v₀ = m v₁ + m v₂

6 0
3 years ago
You go rock climbing with a pack that weighs 70 N and you reach a height of 30 m. how much work did you do to lift your pack? If
Vikentia [17]
When you climb, earth exerts gravitational force on pack in downward direction(pointing towards the center of earth).
In order to climb, you need to work against work done by gravity on the pack.
Hence work done by you = work done by gravity on pack 
                                        = Force x displacement = 70 x 30 = 2100 J.
 
So you need to do 2100 joules of work to lift your pack.

Power is the rate of work done.
Therefore power = work done by you/time(in seconds)
                            =     2100/600 =3.5 watts 
8 0
3 years ago
Which of the following is considered a physical change?
zmey [24]

Answer:

C)evaporating of water

Explanation:that is because waters physical property is lost after evaporating

4 0
3 years ago
Read 2 more answers
What is the process called when the moon begins to fade from a full moon to the new moon?
nataly862011 [7]
Waning is what it’s called
8 0
3 years ago
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