Answer:
, ](https://tex.z-dn.net/?f=%5B16%20%2B%20%28-18%29%5D%28-4%29)
Step-by-step explanation:
Given: The low temperature on Monday was 16°F. The low temperature on Tuesday was 18°F cooler. The low temperature on Wednesday was –4 times Tuesday’s temperature.
To find: expression that can be used to describe the low temperature on Wednesday
Solution:
Temperature on Monday = 16°F
So,
Temperature on Tuesday = 
Temperature on Wednesday = 
So, expression 
can be used to describe the low temperature on Wednesday.
Also,
\,\,\left \{\because (a-b)=\left [ a+(-b) \right ] \right \}](https://tex.z-dn.net/?f=%2816-18%29%28-4%29%3D%5B16%20%2B%20%28-18%29%5D%28-4%29%5C%2C%5C%2C%5Cleft%20%5C%7B%5Cbecause%20%20%28a-b%29%3D%5Cleft%20%5B%20a%2B%28-b%29%20%5Cright%20%5D%20%5Cright%20%5C%7D)
So, expression also represent temperature on Wednesday.
Answer:
Below in bold.
Step-by-step explanation:
The identity is of the form
(a + b)^2 = a^2 + 2ab + b^2.
a) Sqrt 49 = 7 and we need + 28 as the middle coefficient . We get this with
2*7 + 2*7 so the first coefficient is 2*2 = 4.
So * = 4a^2.
(2a + 7)^2 = (2a + 7)(2a + 7) = 4x^2 + 14a + 14a + 49.
b) -6 * -6 = 36 -24 = 2*-6 + 2 *-6 so the last term is 4x^2
c) The middle term must be an 'ab' term.
sqrt 6.25 = 2.5 and sqrt 1/4 = 1/2
So the coefficient of the middle term is 2.5 * 1/2 + 2.5 * 1/2
= 2.5
So the middle term is 2.5ab.
d) The first term will be in b^2.
100 = 10* 10 and we need 2 as a middle term so coefficient of the first term
will be 1/100 or 0.01. as the 2 comes from 0.1 * 10 + 0.01 * 10 and (0.1)^2 = 0.01
So it is 0.01b^2.
The value of x that will make the proportion true is
C. 7
I did my math and I think 41 minuets but are u adding or subracting
Answer:
By exterior angle theorem, we have;
∠DBE = ∠H + ∠HEB = ∠ECD = ∠H + ∠HDC
∴ ∠H + ∠HEB = ∠H + ∠HDC
By addition property of equality, we have
∠HEB = ∠HDC
∠H = ∠H by reflexive property
∴ ΔHCD ~ ΔHEB by Angle Angle AA similarity postulate
∴ HE/HD = EB/DC, by the definition of similarity
Therefore, by cross multiplication, we have;
HE × DC = EB × HD
Therefore, by commutative property of multiplication, we have;
HE × DC = HD × EB
Step-by-step explanation:
