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Olin [163]
2 years ago
14

If LM = MP, then M must be the midpoint of LP? True or False? Im so confused on this!

Mathematics
1 answer:
ikadub [295]2 years ago
6 0

Answer:

true

Step-by-step explanation:

if you have a line LP and midpoint M means M divides LP in to two equal parts ie LM and MP

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PLZ TELL ME IF THIS IS RIGHT!!! THX
emmasim [6.3K]

Answer:

correct

Step-by-step explanation:

x means up and down and it is at -3

y means side to side and it is at -7

5 0
3 years ago
How many degrees warmer is a temperature of 13°F than a temperature of -19°F?
Nata [24]
It'd be 32 degrees F warmer

13-(-19)
=32
8 0
3 years ago
Read 2 more answers
Solve the system of linear equations. 3x−2y=1 9x−6y=3
irakobra [83]
Get the y by itself

-2y= -3x + 1

Divide -2 to everything

y= 3/2x - 1/2


Other equation (get y by itself)

-6y= -9x + 3
y=3/2x - 1/2

Use substitution

3/2x-1/2=3/2-1/2

0=0

All real numbers (any value of x makes the equation true)
8 0
2 years ago
Evaluate................
wolverine [178]

Answer:

h(8q²-2q) = 56q² -10q

k(2q²+3q) = 16q² +31q

Step-by-step explanation:

1. Replace x in the function definition with the function's argument, then simplify.

h(x) = 7x +4q

h(8q² -2q) = 7(8q² -2q) +4q = 56q² -14q +4q = 56q² -10q

__

2. Same as the first problem.

k(x) = 8x +7q

k(2q² +3q) = 8(2q² +3q) +7q = 16q² +24q +7q = 16q² +31q

_____

Comment on the problem

In each case, the function definition says the function is not a function of q; it is only a function of x. It is h(x), not h(x, q). Thus the "q" in the function definition should be considered to be a literal not to be affected by any value x may have. It could be considered another way to write z, for example. In that case, the function would evaluate to ...

h(8q² -2q) = 56q² -14q +4z

and replacing q with some value (say, 2) would give 196+4z, a value that still has z as a separate entity.

In short, I believe the offered answers are misleading with respect to how you would treat function definitions in the real world.

7 0
3 years ago
What is the fewest number of quarters, nickels, and pennies that can be fairly exchanged for 2 quarters, 6 nickels, and 9 pennie
adoni [48]

Answer:

Your answer is 3 quarters, 2 nickels, and 4 pennies

Step-by-step explanation:

2 quarters plus 6 nickels plus 9 pennies is equal to 89 cents. So if we subtract 75(3 quarters) we get 14 which is less than 25 therefore we must only use nickels and pennies from now on. If we take 14 and subtract 10(2 nickels) we get 4 which less than 5 leaving us only to use pennies, which one a piece so it must be 4 pennies. Hope this helps!

4 0
3 years ago
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