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il63 [147K]
3 years ago
5

Mr. Magoo needs to paint on of his bedrooms that is 15ft by 20ft. If he paints only the walls, and each gallon of paint covers 1

00ft2, how many gallons of paint will he need?
Mathematics
2 answers:
trasher [3.6K]3 years ago
8 0

To solve this problem you must apply the proccedure shown below:

1. You have that the total area is obtained by applying the formula for calculate the area of a rectangle and multiply it by the four walls:

At=(4)(15ft)(20ft)\\ A=1,200ft^{2}

2. You know that each gallon of paint covers 100 ft², therefore, you can calculate the amount of gallons needed (which you can call x), if you divide the total area of the walls by the area covered by each gallon:

x=\frac{1,200ft^{2}}{100ft^{2}}=12

The answer is: 12 gallons.

photoshop1234 [79]3 years ago
8 0

Answer:

Step-by-step explanation 15x20=300

300/100=3

the answer is 3

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Will give brainliest
Sonja [21]

The sum of the two <em>rational</em> equations is equal to (3 · n² + 5 · n - 10) / (3 · n³ - 6 · n²).

<h3>How to simplify the addition between two rational equations</h3>

In this question we must use <em>algebra</em> definitions and theorems to simplify the addition of two <em>rational</em> equations into a <em>single rational</em> equation. Now we proceed to show the procedure of solution in detail:

  1. (n + 5) / (n² + 3 · n - 10) + 5 / (3 · n²)      Given
  2. (n + 5) / [(n + 5) · (n - 2)] + 5 / (3 · n²)     x² - (r₁ + r₂) · x + r₁ · r₂ = (x - r₁) · (x - r₂)
  3. 1 / (n - 2) + 5 / (3 · n²)     Associative and modulative property / Existence of the multiplicative inverse
  4. [3 · n² + 5 · (n - 2)] / [3 · n² · (n - 2)]       Addition of fractions with different denominator
  5. (3 · n² + 5 · n - 10) / (3 · n³ - 6 · n²)       Distributive property / Power properties / Result

To learn more on rational equations: brainly.com/question/20850120

#SPJ1

4 0
2 years ago
What is the unit rate for this?<br> Time: 1, 2, 3, 4 <br> Amount: 0.6, 1.2, 1.8, 2.4
Debora [2.8K]

Answer:

1:0.6

Step-by-step explanation:

4 0
3 years ago
I need help with number 1 and 2.
olya-2409 [2.1K]
1.b 2.34 is the correct answer 
8 0
4 years ago
The question is in the picture.
dangina [55]
<h2><u>Part A:</u></h2>

Let's denote no of seats in first row with r1 , second row with r2.....and so on.

r1=5

Since next row will have 10 additional row each time when we move to next row,

So,

r2=5+10=15

r3=15+10=25

<u>Using the terms r1,r2 and r3 , we can find explicit formula</u>

r1=5=5+0=5+0×10=5+(1-1)×10

r2=15=5+10=5+(2-1)×10

r3=25=5+20=5+(3-1)×10

<u>So for nth row,</u>

rn=5+(n-1)×10

Since 5=r1 and 10=common difference (d)

rn=r1+(n-1)d

Since 'a' is a convention term for 1st term,

<h3><u>⇒</u><u>rn=a+(n-1)d</u></h3>

which is an explicit formula to find no of seats in any given row.

<h2><u>Part B:</u></h2>

Using above explicit formula, we can calculate no of seats in 7th row,

r7=5+(7-1)×10

r7=5+(7-1)×10 =5+6×10

r7=5+(7-1)×10 =5+6×10 =65

which is the no of seats in 7th row.

8 0
3 years ago
Please help ASAP thank youu!!
Gennadij [26K]

Answer:

1. (-5)

Step-by-step explanation:

Here you go, glad to help :)

4 0
3 years ago
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