<u>Given </u><u>:</u><u>-</u>
<u>To </u><u>Find</u><u> </u><u>:</u><u>-</u>
- To convert the given equation into standard form.
<u>Solution</u><u> </u><u>:</u><u>-</u>
As we know that the standard form of the line is ,
ax + by + c = 0
So the given equation is ,
y = 2/5x -1/3
y = 6x - 5/15
15y = 6x - 5
6x -15y -5 = 0
<u>Hence</u><u> the</u><u> required</u><u> </u><u>equation</u><u> of</u><u> the</u><u> line</u><u> is</u><u> </u><u>6</u><u>x</u><u> </u><u>-15y-5=</u><u>0</u><u>.</u>
Supplementary angles definition: They add up to 180°
There are several ways to prove a parallelogram:
1. Opposite sides theorem converse
2. Opposite angles theorem converse
3. Parallelogram diagonals theorem converse
4. Parallel congruent sides theorem
∠P + ∠Q = 180° --1
∠P + ∠S = 180° --2
1: ∠P = 180° - ∠Q
Sub 1 into 2:
180° - ∠Q + ∠S = 180°
180° + ∠S = 180° + ∠Q
∠S = ∠Q
Or you can try saying the opposite sides are parallel, since they are interior angles and those are straight lines
It's the last option again. You have 1 linear factor (3<em>x</em>) and 2 copies of a quadratic factor (<em>x</em>² + 10), and the partial fractions with the quadratic factor need to have a linear polynomial in the numerator.
Answer:
c
Step-by-step explanation: