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Deffense [45]
3 years ago
6

2Ag + H2S ➞ Ag2S + H2

Chemistry
2 answers:
erik [133]3 years ago
8 0

Answer:

c

Explanation:

i did the usatest prep

NeX [460]3 years ago
4 0

Answer:

The correct answer is <em>C)  Two atoms of silver are needed to complete the reaction.</em>

Explanation:

The Law of Conservation of Matter postulates that "the mass is not created or destroyed, only transformed." This means that the reagents interact with each other and form new products with physical and chemical properties different from those of the reagents because the atoms of the substances are ordered differently. But the amount of matter or mass before and after a transformation (chemical reaction) is always the same, that is, the quantities of the masses involved in a given reaction must be constant at all times, not changing in their proportions when the reaction ends.

Then, taking into account the Law of Conservation of Matter, as an atom cannot be created or destroyed in a chemical reaction, the number of atoms that are present in the reagents has to be equal to the number of atoms present in the products.

For this, the chemical equation must be balanced. For that, you must first look at the subscripts next to each atom to find the number of atoms in each compound in the equation. If the same atom appears in more than one molecule, you must add its quantities. On the other hand, the coefficients located in front of each molecule indicate the amount of each molecule for the reaction. This coefficient can be modified to balance the equation, just as you should never alter the subscripts. By multiplying the coefficient mentioned by the subscript, you get the amount of each element present in the reaction.

In this case:

Left side: 2 silver  (Ag), 2 hydrogen (H) and 1 sulfur (S)

Right side: 2 silver  (Ag), 2 hydrogen (H) and 1 sulfur (S)

In this case the equation is balanced because you have the same amount of all the elements on each side of the reaction. And <u><em>the 2 in front of 2Ag indicates that,since silver is a reagent, two atoms of silver are needed to complete the reaction. (option C).</em></u>

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Solid sodium iodide is slowly added to a solution that is 0.0050 M Pb 2+ and 0.0050 M Ag +. [K sp (PbI 2) = 1.4 × 10 –8; K sp (A
UkoKoshka [18]

Answer:

[Ag⁺] = 5.0x10⁻¹⁴M

Explanation:

The product solubility constant, Ksp, of the insoluble salts PbI₂ and AgI is defined as follows:

Ksp(PbI₂) = [Pb²⁺] [I⁻]² = 1.4x10⁻⁸

Ksp(AgI) = [Ag⁺] [I⁻] = 8.3x10⁻¹⁷

The PbI₂ <em>just begin to precipitate when the product  [Pb²⁺] [I⁻]² = 1.4x10⁻⁸</em>

<em />

As the initial [Pb²⁺] = 0.0050M:

[Pb²⁺] [I⁻]² = 1.4x10⁻⁸

[0.0050] [I⁻]² = 1.4x10⁻⁸

[I⁻]² = 1.4x10⁻⁸ / 0.0050

[I⁻]² = 2.8x10⁻⁶

<h3>[I⁻] = 1.67x10⁻³</h3><h3 />

So, as the [I⁻] concentration is also in the expression of Ksp of AgI and you know concentration in solution of I⁻ = 1.67x10⁻³M:

[Ag⁺] [I⁻] = 8.3x10⁻¹⁷

[Ag⁺] [1.67x10⁻³] = 8.3x10⁻¹⁷

<h3>[Ag⁺] = 5.0x10⁻¹⁴M</h3>

6 0
3 years ago
A mixture of 0.600 mol of bromine and 1.600 mol of iodine is placed into a rigid 1.000-L container at 350°C.
kaheart [24]

The equilibrium constant of the reaction is 282. Option D

<h3>What is equilibrium constant?</h3>

The term equilibrium constant refers to the number that often depict how much the process is able to turn the reactants in to products. In other words, if the reactants are readily turned into products, then it follows that the equilibrium constant will be large and positive.

Concentration of bromine = 0.600 mol /1.000-L = 0.600 M

Concentration of iodine = 1.600 mol/1.000-L =  1.600M

In this case, we must set up the ICE table as shown;

              Br2(g) + I2(g) ↔ 2IBr(g)

I          0.6            1.6           0

C      -x                -x             +2x

E    0.6 - x         1.6 - x       1.190

If 2x = 1.190

x = 1.190/2

x = 0.595

The concentrations at equilibrium are;

[Br2] = 0.6 -  0.595 = 0.005

[I2] =   1.6 - 0.595 = 1.005

Hence;

Kc = [IBr]^2/[Br2] [I2]

Kc = ( 1.190)^2/(0.005) (1.005)

Kc = 282

Learn more about equilibrium constant:brainly.com/question/15118952

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4 0
2 years ago
How do I solve the following word problem: The half-life of Phosphorus - 32 is 14.3 days. It is used to study a plant's use of f
BaLLatris [955]

Half life is the time that it takes for half of the original value of some amount of a radioactive element to decay.

We have the following equation representing the half-life decay:

A=A_o\times2^{(-\frac{t}{t_{half}})_{}_{}}

A is the resulting amount after t time

Ao is the initial amount = 50 mg

t= Elapsed time

t half is the half-life of the substance = 14.3 days

We replace the know values into the equation to have an exponential decay function for a 50mg sample

A=\text{ 50 }\times2^{\frac{-t}{14.3}}

That would be the answer for a)

To know the P-32 remaining after 84 days we have to replace this value in the equation:

\begin{gathered} A=\text{ 50 }\times2^{\frac{-84}{14.3}} \\ A=0.85\text{ mg} \end{gathered}

So, after 84 days the P-32 remaining will be 0.85 mg

4 0
1 year ago
A reaction that occurs in the internal combustion engine is N₂(g) + O₂(g) ⇄ 2NO(g) (c) What is the significance of the different
vodomira [7]

The response would become spontaneous if the value of  ΔG° was negative.

According to the estimated value of  ΔG°, it is shown that  ΔG° value decreases as temperature value increases. The value shifts from being more favorable to being less favorable. It would appear that the value of  ΔG° would be negative at a specific temperature, causing the reaction to occur spontaneously.

The reaction is in an equilibrium state if  ΔG = 0. If ΔG < 0, the reaction is spontaneous in the direction written. The relationship between terms from the equilibrium is paralleled by the relevance of the sign of a change in the Gibbs free energy.

Learn more about ΔG° here:

brainly.com/question/14512088

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8 0
1 year ago
A(n) ____________________ has a rectangular shape and contains a cell wall, chloroplasts, and one large vacuole.
tiny-mole [99]
I’m pretty sure the answer is “plant cell”
7 0
3 years ago
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