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3 years ago

Which of these species are free radicals? check all that apply. check all that apply. no2 no o o2 o3?

1 answer:

4 0

Answer: NO2, NO, and O2.

<span>Free radicals are toxic substances produced by the body. In normal circumstances,the body can neutralize but<span> when the level of these substances is to much,they accumulate and can generate diseases, such as osteoporosis and cancer.</span></span>

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Properties of iron, barium, and phosphorus. Explain why nails are made of iron but they are never made of barium or phosphorus.

bearhunter [10]

Nails are made up of iron not of phosphorus and barium.

As both phosphorous and barium are relatively weaker than iron ,phosphorus breaks easily and barium is also fairly weak. Iron nails are already also not that strong, but their weight and strength are sufficient.

So the nails are made up of iron.

3 0

3 years ago

Energy cannot be created or destroyed. Does the statement describe a scientific law?

LekaFEV [45]

Yes, the law of thermodynamics, or Law of Conservation of Energy

3 0

3 years ago

How do chemists model the valence electrons in a metal

Bumek [7]

Answer:

the valence electrons of atoms in a pure metal can be modeled as a sea of electrons

5 0

2 years ago

Aluminum reacts with sulfur gas to produce aluminum sulfide. a) What is the limiting reactant? What is the excess reagent? b) Ho

Sophie [7]

Answer:

a) Limiting: sulfur. Excess: aluminium.

b) 1.56g Al₂S₃.

c) 0.72g Al

Explanation:

Hello,

In this case, the initial mass of both aluminium and sulfur are missing, therefore, one could assume they are 1.00 g for each one. Thus, by considering the undergoing chemical reaction turns out:

$2Al(s)+3S_2(g)\rightarrow 2Al_2S_3(s)\\$

a) Thus, considering the assumed mass (which could be changed based on the one you are given), the limiting reagent is identified as shown below:

$n_S^{available}=1.00gS_2*\frac{1molS_2}{64gS_2} =0.0156molS_2\\n_S^{consumed\ by \ Al}=1.00gAl*\frac{1molAl}{27gAl}*\frac{3molS_2}{2molAl}=0.0556molS_2$

Thereby, since there 1.00g of aluminium will consume 0.0554 mol of sulfur but there are just 0.0156 mol available, the limiting reagent is sulfur and the excess reagent is aluminium.

b) By stoichiometry, the produced grams of aluminium sulfide are:

$m_{Al_2S_3}=0.0156molS_2*\frac{2molAl_2S_3}{3molS_2} *\frac{150gAl_2S_3}{1molAl_2S_3} =1.56gAl_2S_3$

c) The leftover is computed as follows:

$m_{Al}^{excess}=(0.0556-0.0156)molS_2*\frac{2molAl}{3molS_2}*\frac{27gAl}{1molAl} =0.72 gAl\\$

NOTE: Remember I assumed the quantities, they could change based on those you are given, so the results might be different, but the procedure is quite the same.

Best regards.

7 0

3 years ago

Pierce conducts an experiment in which waves collide in a way that the energy increases, which means that has occurred

Vikki [24]

<h2>Answer:</h2>

It means the waves collides and constructive interference occurred.

<h3>Explanation:</h3>

If the two waves coming from the opposite direction collide with each other, there are two way of their interference.

Constructive interference: An interference which results in the increase in energy. And it is when crust of a wave comes on the crust of second wave.
Destructive interference: An interference which results in decrease in energy of the resulting wave and colliding waves cancel the result of each other.

Hence in experiment there will be constructive interference.

8 0

3 years ago

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