Answer:
47
Step-by-step explanation:
should be the correct answer
Answer:
The whole number dimension that would allow the student to maximize the volume while keeping the surface area at most 160 square is 6 ft
Step-by-step explanation:
Here we are required find the size of the sides of a dunk tank (cube with open top) such that the surface area is ≤ 160 ft²
For maximum volume, the side length, s of the cube must all be equal ;
Therefore area of one side = s²
Number of sides in a cube with top open = 5 sides
Area of surface = 5 × s² = 180
Therefore s² = 180/5 = 36
s² = 36
s = √36 = 6 ft
Therefore, the whole number dimension that would allow the student to maximize the volume while keeping the surface area at most 160 square = 6 ft.
The answered the question is X=5
9514 1404 393
Answer:
y = 1
Step-by-step explanation:
Recognize that 25 and 125 are powers of 5 and rewrite the equation in terms of powers of 5.
The applicable rules of exponents are ...
(a^b)^c = a^(bc)
(a^b)/(a^c) = a^(b-c)
(a^b)(a^c) = a^(b+c)
__
Your equation can be written as ...
Now this can be solved as an ordinary linear equation.
8 = 8y . . . . . . add 5y to both sides
1 = y . . . . . . . divide by 8
The solution is y = 1.
3 + 1.75m
This represents 1.75 per mile plus a one time 3 charge.
Another way this can be written is
(1.75m + 6) - 3
This is a less efficient way, but represents the same. It is 1.75 per mile, this is plus 6, therefore we add the -3 outside the parenthesis so it evens out to +3 as the base charge.
Example: Lets say its 3 miles.
3 + 1.75 (3) = 8.25
(1.75 (3) + 6) - 3 = 8.25
