1) The lengths of the other 2 sides are 51 feet.
Isosceles triangles have at least 2 equal sides. The base is 60 feet, so we can assume that the other 2 sides are equal
162 = 60 + 2x
x = the equal sides of the triangle.
162 - 60 = 102
102 = 2x
Divided by 2
51 = x
51 + 51 = 102. 102 + 60 = 162
2)
Pool 1: 311.38ft.
8*19.4 = 155.2
8 * 5.7 * 2 = 91.2
5.7 * 5.7 = 32.49/2 (because its a triangle) = 16.254*4 = 64.98
155.2 + 91.2 + 64.98 = 311.39
Pool 2: Either 863.94ft or 484 + 121πft
22 * 22 = 484
22/2 = 11, So, the radius of the half circle is 11
Circle area = (pi)r^2
11*11 = 121
pi * 121 = 121pi
Using 3.14 substitute: 3.14 * 121 = 379.94
379.94 + 484 = 863.94
Pool 3: 207ft
Rhombus area = pq/2
18 * 12 = 216
216/2 = 108
11 * 18 = 198/2 = 99
99 + 108 = 207
Answer: 0 = − 2, Is the answer I think. Sorry if it's wrong.
Answer:
the perimeter is 28 and the area is 49
Step-by-step explanation:
a square has equals sides and i counted seven on each side for the perimeter. you multiply seven by seven to find the area
Answer:
x=25
Step-by-step explanation:
First, we add all like terms. Then, we solve for x.
We can rearrange some things because order does not matter with addition. Next, we just use basic equation solving techniques.
9514 1404 393
Answer:
√35 +3√7 -6 . . . square units
Step-by-step explanation:
The area can be figured a number of ways. The figure can be divided into parts, and the areas of those parts added.
Or, the area of the enclosing rectangle can be found, and the rectangle at upper right that is not shaded can be subtracted from that. We choose the latter.
The overall width is the sum of the given partial widths:
width = (√7 -2) + (2) = √7
Then the area of the bounding rectangle is ...
A = LW = (√5 +3)(√7) = √35 +3√7
The area of the upper right empty-space is ...
A = LW = (3)(2) = 6
Then The area of the shaded figure is ...
√35 +3√7 -6
