Question

write an equation for the line that is parallel to the given line ans that passes through the given point: y=5/2x-10;(-6,-29)

Answer 1

Answer:

all work is shown and pictured

Answer 2

Answer:

$y=\frac{5}{2}x-14$

Step-by-step explanation:

We are asked to write equation that is parallel to $y=\frac{5}{2}-10$ and passes through point $(-6,-29)$.

We know that parallel lines have same slope, so the slope of parallel line would be $\frac{5}{2}$.

Now, we will substitute $m=\frac{5}{2}$ and coordinates of point $(-6,-29)$ in slope-intercept form of equation as:

$y=mx+b$

$-29=\frac{5}{2}(-6)+b$

$-29=5(-3)+b$

$-29=-15+b$

$-29+15=-15+15+b$

$-14=b$

Therefore, our required equation would be $y=\frac{5}{2}x-14$.