Question

A circular disk of radius 0.015 m rotates with a constant angular speed of 5.0 rev/s. what is the acceleration of a point on the edge of the disk?

Answer 1

Answer:
linear acceleration = 14.8 m/sec^2

Explanation:
The linear acceleration of a rotating body can be calculated using the following rule:
linear acceleration = (radius)*(angular velocity)^2
We are given that:
radius = 0.015 m
angular velocity = 5.0 rev/s = 5.0 * 2 * pi = 10 pi rad
Substitute with the givens in the above equation to get the linear acceleration as follows:
linear acceleration = (0.015) * (10*pi)^2 = 14.8 m/sec^2

Hope this helps :)