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malfutka [58]
4 years ago
8

If you were given a 16.0 ml sample of solution A, describe how you could determine the mass of the sample using only your graph

answer
Chemistry
1 answer:
rewona [7]4 years ago
8 0
A density of the substance is an intrinsic property. Each substance has its own value of density, and it is constant. Since density is equal to mass over volume, a graph of mass vs volume would have a constant slope equal to density. So, it will be a linear graph. The mass is in the y-axis, and the volume is on the x-axis. Locate V = 16 mL on the x-axis, project it upwards until it intersects with the linear graph, then, move towards the left to determine the corresponding y-value, represented by the mass.
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If you were to use Lewis theory to predict the formula for the compound between rubidium and fluorine, it would most likely be:
goldenfox [79]

<u>Answer:</u> The formula of the compound formed between rubidium and fluorine is RbF

<u>Explanation:</u>

Ionic bond is defined as the bond which is formed by complete transfer of electrons from one atom to another atom.

The atom which looses the electron is known as electropositive atom and the atom which gains the electron is known as electronegative atom. This bond is usually formed between a metal and a non-metal.

Rubidium is the 37th element of the periodic table having electronic configuration of 1s^22s^22p^63s^23p^64s^23d^{10}4p^65s^1

This will loose 1 electron to form Rb^+ ion

Fluoride is the 9th element of the periodic table having electronic configuration of 1s^22s^22p^5

This will gain 1 electron to form F^- ion

To form RbF compound, 1 rubidium ion is needed to neutralize the charge on fluoride ion

The formation of the given compounds is shown in the image below.

4 0
3 years ago
Identify the type of sugar corresponding to each name. Sucrose Lactose Fructose Starch Glucose
hammer [34]

Answer: Please see answers in explanation column

Explanation:

Name                Type of sugars

Sucrose               Disaccharide

Sucrose, also called table sugar with molecular formulae C12H22O11  is a disaccharide  composed of two monosaccharides ( 50%glucose + 50%  fructose.).

Lactose                 Disaccharide

 Lactose with molecular formula C12H22O11, found in milk is a disaccharide composed of two monosaccharides (galactose and glucose).

Fructose                 Monosaccharide  

Fructose with molecular formulae C6H12O6 is a natural sugar mostly found in fruits.

Starch                  Polysaccharide

Starch ,a complex carbohydrate with molecular formula  (C6H10O5)n,  is a Polysaccharide containing many  units of glucose joined together by 1,4 linkages. Sources of starch can be found in the parts of plants( roots, tubers etc).

Glucose                 monosaccharides

Glucose, is a simple sugar (monosaccharides) with the molecular formula C6H12O6.  It is found in parts of plants  as well as in humans and known as blood sugar because of its location in the bloodstream.

8 0
3 years ago
______collisions describe the process by which particles collide and transfer energy without loss of energy.
Elina [12.6K]

Answer:

A. Elastic

Explanation:

an elastic collision is one which there is no overall loss of kinetic energy

5 0
3 years ago
Determine the freezing point of a water solution of fructose (C6H12O6) made by dissolving 92.0 g of fructose in 202 g of water.
Naya [18.7K]

Answer:

THE FREEZING POINT OF A WATER SOLUTION OF FRUCTOSE MADE BY DISSOLVING 92 g OF FRUCTOSE IN 202g OF WATER IS -4.70 ◦C

Explanation:

To calculate the freezing point of a water solution of fructose,

1. calculate the molar mass of Fructose

( 12 * 6 + 1*12 + 16*6) =72 + 12 +96 = 180 g/mol

2. calculate the number of moles of fructose in the solution

number of moles = mass / molar mass

n = 92 g / 180 g/mol

n = 0.511 moles.

3. calculate the molarity of the solution

molarity = moles / mass of water in kg

molarity = 0.5111 / 202 g /1000 g

molarity = 0.5111 / 0.202

molarity = 2.529 M

4. calculate the change in the freezing point of pure solvent and solution ΔTf

ΔTf = Kf * molarity of the solute

Kf = 1.86 ◦C/m for water

ΔTf = 1.86 * 2.529

ΔTf = 4.70 C

5. the freezing point is therefore

0.00 ◦C - 4.70 ◦C = -4.70 ◦C

4 0
3 years ago
Read 2 more answers
As the tempreture of a liquid increases the solubility of a liquid of that liquid
anzhelika [568]
As the temperature increases, the solubility of the solute in the liquid also increases.  This is due to the fact that the increase in energy allows the liquid to more effectively break up the solute.  The additoin of energy also shifts the equilibrium of the reation to the right since it takes energy to dissolve most things and you are adding more of it (this is explained with Le Chatlier principles).

I hope this helps and also I assumed that your question involved the solubility of an ionic substance in a solvent like water.  If that was not your question feel free to say so in the comments so that I can answer your actually question.
8 0
3 years ago
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