Answer:
Step-by-step explanation:
Given that,
ABC is an Isosceles triangle.
In an Isosceles triangle the opposite sides ( AB =AC) are equal; Their base angles ( < ABD = < ACD) are also equal to each other.
It is als given that D is the mid point of BC.
i.e., BD = CD
Therefore,
By SAS theorem of congruency of triangles,
ABD = ACD
If this is the answer required, hope it helps...
Answer:
b=2
Step-by-step explanation:
1.1 Pull out like factors :
4b - 8 = 4 • (b - 2)
Equation at the end of step 1 :
Step 2 :
Equations which are never true :
2.1 Solve : 4 = 0
This equation has no solution.
A a non-zero constant never equals zero.
Solving a Single Variable Equation :
2.2 Solve : b-2 = 0
Add 2 to both sides of the equation :
b = 2
One solution was found :
b = 2
Answer:
Step-by-step explanation:
Sin theta is the ratio of side opposite over hypotenuse of a reference angle situated at the origin in an x-y coordinate plane. If sec theta is negative, then the only quadrant where sin is positive AND sec is negative is quadrant 2. Remember that sec theta is the inverse of cos theta. Puttling our right triangle in QII, the side measuring 7 is across from the angle and the hypotenuse is 11. In order to find the cos theta and tan theta, we need the side adjacent to the angle. Use Pythagorean's Theorem to find the side adjacent.
and
and
so

Remember that this value is why the sec is negative. Because x is negative in QII, the cos theta is side adjacent over hypotenuse:
and

But we should probably rationalize that denominator, so

Answer: N0. There are not enough teacher signatures.
<u>Step-by-step explanation:</u>
Total signatures needed:
x 1200 = 150
Total signatures received: 150
********************************************************************
Teacher signatures needed:
x 150 = 6
Teacher signatures received:
x 150 = 4
<em>Side note: If there are
student signatures then there are
teacher signatures, because the student plus teacher signatures must equal 100%</em>