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Anon25 [30]
3 years ago
14

Lindsey throws a hard rubber ball against a wall. Describe the forces that act on the ball when it hits the wall and how the for

ces affect the motion of the ball. How do the action force and reaction force compare?
Physics
2 answers:
Zinaida [17]3 years ago
8 0

Answer:

the reaction force is the bounce back

Explanation:

the motion force is how hard she throws it

hope this helps

Elanso [62]3 years ago
5 0
Well there have to be two forces acting apon a object for there to be a change
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An object begins x=75.2 m and undergoes a displacement of -48.7 m. what is its final position?
xz_007 [3.2K]

Answer:

26.5 m

Explanation:

x_{o} = initial position of the object = 75.2 m

x  = final position of the object

d  = displacement of the object = - 48.7  

Displacement of the object is given as the difference of final and initial position of the object

d = x - x_{o}

Inserting the values

- 48.7 = x - 75.2

x = 26.5 m

8 0
3 years ago
How does The centripetal fotce change if the car has less Mass?​
vaieri [72.5K]

Answer:

The centripetal force acting on the car is proportional to the mass of the car.

Explanation:

Let,

The mass of the car be 'm'

The velocity of the car moving in the curved path be 'v'

The radius of the curved path be 'r'

According to physics, a body moving ion circular path experience a force directed along the radius of the path. This force is called centripetal force.

The formula for centripetal force is,

                                   <em>F = mv²/r</em>

Where,

                                      a = v²/r

So, if the mass of the car changes, the centripetal force also changes proportionally according to the above equation.

5 0
3 years ago
Two loops of wire are arranged so that a changing current in one will induce a current in the other. If the current in the first
patriot [66]

Answer:

The current in the second loop will stay constant

Explanation:

Since the induced emf in the second coil, ε due to the changing current i₁ in the first wire loop ε = -Mdi₁/dt where M = mutual inductance of the coils and di₁/dt = rate of change of current in the first coil = + 1 A/s (positive since it is clockwise)

Now ε = i₂R where i₂ = current in second wire loop and R = resistance of second wire loop.

So,  i₂R = -Mdi₁/dt

i₂ = -Mdi₁/dt/R

Since di₁/dt = + 1 A/s,

i₂ = -Mdi₁/dt/R

i₂ = -M × + 1 A/s/R

i₂ = -M/R

Since M and R are constant, this implies that i₂ = constant

<u>So, the current in the second wire loop will stay constant.</u>

3 0
3 years ago
Which of the following must be the same before and after a chemical reaction?
madam [21]

Answer: Option (D) is the correct answer.

Explanation:

A chemical reaction is defined as the reaction which causes change in chemical composition of a substance.

According to law of conservation of mass, mass can neither be created nor it can be destroyed. It can only be changed from one form to another.

For example, H^{+} + Cl^{-} \rightarrow HCl

Here, total mass of reactants = (1.008 + 35.453) g/mol = 36.461 g/mol

Whereas total mass of products = 36.461 g/mol

This shows that mass remains the same before or after the reaction.

Similarly, the number of atoms of the type involved will remains the same as no change in their nucleus is occurring.

Thus, we can conclude that the following must be the same before and after a chemical reaction.

  • The sum of the masses of all substances involved.
  • The number of atoms of the type involved.
6 0
3 years ago
A water balloon is thrown at an angle of 30° with a velocity of 40 m/s. How long do you have to move out of the way if the ballo
boyakko [2]

Answer:

t=0.58s

Explanation:

We can consider only the horizontal component since the horizontal component of the velocity is constant (v_x=vcos\theta), and we want to know how much time it takes for the balloon to travel a horizontal distance d_x at that speed. The definition of (horizontal) velocity is v_x=\frac{d_x}{t}, so we have:

t=\frac{d_x}{v_x}=\frac{d_x}{vcos\theta}=\frac{(20m)}{(40m/s)cos(30^{\circ})}=0.58s

6 0
3 years ago
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