While ionic bonds join metals to nonmetals, and covalent bonds join nonmetals to nonmetals, metallic bonds are responsible for the bondingbetween metal atoms. In metallic bonds, the valence electrons from the s and p orbitals of the interacting metal atoms delocalize.
I hope that this answer helps you out
Hi there!
We can begin by finding the acceleration of the block.
Use the kinematic equation:

The block starts from rest, so:

Now, we can do a summation of forces of the block using Newton's Second Law:

mb = mass of the block
T = tension of string
Solve for tension:

Now, we can do a summation of torques for the wheel:

Rewrite:

We solved that the linear acceleration is 1.5 m/s², so we can solve for the angular acceleration using the following:

Now, plug in the values into the equation:

The radius of the prop blade of an airplane is determined as 4.25 m.
<h3>
Radius of the prop blade</h3>
The radius of the prop blade of an airplane is calculated as follows;
a = v²/r
where;
- v is the linear speed
- r is the radius of the prop blade
- a is the centripetal acceleration
r = v²/a
r = (875²)/(180,000)
r = 4.25 m
Thus, the radius of the prop blade of an airplane is determined as 4.25 m.
Learn more about centripetal acceleration here: brainly.com/question/79801
#SPJ1
<span>When t=0, v=0, d=0
When t=tf, v=41m/s, d=3.5m
We have 2 formulas – the ones corresponding to uniformly accelerated linear movement:
vf=a*t+vo
d=(1/2)*a*t^2+vo*t
Let’s put the data in the formulas:
41m/s=a*t+0=a*t
3.5m=(1/2)*a*t^2+0*t=1/2*a*t^2
You can use a variety of methods to find t and a. I will choose substitution.
t=(41m/s)/a
3.5m=(1/2)*a*((41m/s)/a)^2=(1/2)*a*(41m/s)^2/a^2=(1/2)*(41m/s)^2/a
a=(1/2)*(41m/s)^2/(3.5m)=(1/2)*41^2(m^2/s^2)/(3.5m) a=41^2(m/s^2)/( 2*3.5)=240m/s^2</span>
given that initial velocity is

deceleration is given as

now we have to find the distance covered in 16 s



so it will cover 137.6 m distance
part b)
in order to find the final speed



so its speed will be 6.2 m/s