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Mumz [18]
3 years ago
12

Suppose you are driving in a convertible with the top down at constant speed. You point a rifle straight upward and fire it. In

the absence of air resistance, would the bullet land
(a) behind you,
(b) ahead of you, or
(c) in the barrel of the rifle?
Physics
1 answer:
lyudmila [28]3 years ago
4 0

Answer:

(c) in the barrel of the rifle

Explanation:

When we are moving in a convertible with constant speed so as per inertia all the objects are moving with same speed as that the speed of convertible.

So here we can say that bullet when shot from the rifle then its speed is same as that of convertible in horizontal direction

So here we can say that if air friction is absent then bullet will move same horizontal distance as the distance moved by you in the convertible

so after it it will reach again at the same position then the displacement of you and bullet is same in horizontal direction so we can say that correct answer will be

(c) in the barrel of the rifle

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A high diver of mass 51.7 kg steps off a board 10.0 m above the water and falls vertical to the water, starting from rest. If he
zmey [24]

Answer:

851.33 N

Explanation:

Using newton;s equation of motion,

v² = u² + 2gh ......... Equation 1

Where v = final velocity, u = initial velocity, g = acceleration due to gravity, h = height

Given: u = 0 m/s(from rest), h = 10 m g = 9.8 m/s².

Substitute into equation 1

v² = 0² + 2(9.8)(10)

v² = 196

v = √196

v = 14 m/s.

Note: As the Diver touches the water,  u = 14 m/s and v = 0 m/s( stopped)

Using,

d = (v+u)t/2 .............. equation 2

Where d = distance moved by the diver in water before its motion stopped, t = time taken before it comes to rest

Given: v = 0 m/s, u = 14 m/s t = 2.10 s

Substitute into equation 2

d = (0+14)2.1/2

d = 14.7 m.

Finally

work done by the water to stop the diver = potential energy of the diver

F×d = mgh'................Equation 3

Where F = force of the diver in water, d = distance of the diver in the water, m = mass of the diver, g = acceleration due to gravity, h' = height of the diver from the point of fall to the point where he comes to rest

making F the subject of the equation,

F = mgh/d ............ Equation 4

Given: m = 51.7 kg, h = 10 m, g = 9.8 m/s², d = 14.7 m.

Substitute into equation 4

F = 51.7(10+14.7)(9.8)/14.7

F = 851.33 N

Hence the upward force the water exert on her = 851.33 N

8 0
3 years ago
What mRNA sequence would result from the following DNA sequence?
Nezavi [6.7K]

Answer:

UAC CUG AGG AUC

Explanation:

<em>The mRNA sequence from ATG GAC TCC TAG DNA sequence would be </em><em>UAC CUG AGG AUC.</em>

<u>According to Chargaff's base pairing rule, the purine bases always pair with pyrimidine bases. Specifically, Adenine base must pair with Thymine base while Guanine base must pair with Cytosine base. In RNA, Thymine base is replaced with Uracil base.</u>

Hence:

ATG   GAC   TCC   TAG will pair with

UAC   CUG   AGG   AUC

5 0
3 years ago
Who actually asked Abraham to sacrifice his son?
pochemuha

I think god did ??? I searched it up okay

7 0
2 years ago
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A 4.8 mF capacitor in series with a 500 Ω resistor is connected, by a switch, to a 12 V battery. The current through the resisto
ad-work [718]

Answer:

Current will be 81.7 mA

Which is not given in bellow option

Explanation:

We have given  capacitance C=4.8mF=4.8\times 10^{-3}F

Resistance R = 500 ohm

Voltage V = 12 volt

We know that time constant of RC circuit of RC circuit is given by

\tau =RC=500\times 4.8\times 10^{-3}=2.4sec

Time is given as t = 1 sec

We know that current in RC circuit is given by

i=\frac{v}{R}(1-e^{\frac{-t}{\tau }})

So current i=\frac{12}{500}(1-e^{\frac{-1}{2.4 }})=0.00817A=81.7mA

Which is not given in the following option

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3 years ago
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What is the Orbital Notation for Radon
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Answer:

[Rn]7s2

Explanation:

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