The distance is 28 meters, and the displacement is -4.
For the distance it would be 12 + 16 = 28.
For the displacement it would be 12 - 16 = -4.
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The y-component of the acceleration is 
Explanation:
The y-component of the ice skater acceleration can be calculated with the equation

where
is the y-component of the final velocity
is the y-component of the initial velocity
t is the time elapsed
Here we have:
- Initial velocity is
at
, so its y-component is 
- Final velocity is
at
, so its y-component is 
The time elapsed is
t = 8.33 s
Therefore, the y-component of the acceleration is

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Answer:
<em>the ball travels a distance of 8.84 m</em>
Explanation:
Range: Range is defined as the horizontal distance from the point of projection to the point where the projectile hits the projection plane again.
R = (U²sin2∅)/g.............................. Equation 1
Where R = range, U = initial velocity, ∅ = angle of projection, g = acceleration due to gravity.
<em>Given: U = 10 m/s, ∅ = 60°</em>
<em>Constant: g = 9.8 m/s²</em>
Substituting these values into equation 1
R = [10²×sin(2×60)]/9.8
R = (100sin120)/9.8
R = 100×0.8660/9.8
R = 86.60/9.8
R = 8.84 m
<em>Therefore the ball travels a distance of 8.84 m</em>
It's velocity when it strikes the ground is. D. 232.9 kg.m/s<span>.
</span>
I hope this helps!!!