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arsen [322]
3 years ago
8

Lee and Maya are collecting leaves for an art project lee collects 25/100 of the total number leaves needed. Maya collects 4/10

of the total number of leaves needed what fraction of the total number of leaves did they collect altogether ?
Mathematics
1 answer:
MrRissso [65]3 years ago
6 0

Answer:  The answer is \dfrac{13}{20}.


Step-by-step explanation:  Given that Lee and Maya are collecting leaves for an art project. Let'x' be the total number of leaves needed in the project.

Then, the number of leaves collected by Lee is given by

L_\ell=\dfrac{25}{100}x,

and the fraction of the leaves collected by Maya is given by

M_\ell=\dfrac{4}{10}x.

Therefore, the total number of leaves collected by Lee and Maya altogether is

L=L_\ell+M_\ell=\dfrac{25}{100}x+\dfrac{4}{10}x=\dfrac{25+40}{100}x=\dfrac{65}{100}x=\dfrac{13}{20}x.

Thus, the total fraction of the leaves collected by Lee and Maya is

\dfrac{13}{20}.


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Answer:

Kindly check explanation

Step-by-step explanation:

Total Number of pens = 5

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A.) number of defective pens selected :

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It is possible that no defective pen will be selected ; 1 defective will be chosen or both pens are defective.

2.)

Defective as Success (since selecting a defective pen is the point of interest.

3.)

Since selection is done without replacement

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P(success on first selection) = 2/5

P(success on second selection) = 1/4

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3 years ago
A circle has a diameter of 22mm. What is its circumference ?
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Answer:

22\pi

Step-by-step explanation:

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7 0
3 years ago
Read 2 more answers
e) Given the following: Let X = {1, 2, 3, 4) and a relation R on X as R= {(1,2), (2,3), (3,4)}. Find the reflexive and transitiv
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Answer:

The answer is \{(1,1),(2,2),(3,3),(4,4),(1,2)(2,3)(3,4),(1,3),(1,4)\}

Step-by-step explanation:

Remember that a reflexive relation R\subset \mathcal{P}(X), where \mathcal{P}(X) is the power set of X, is one which conteins the ordered pairs of the form (a,a), for a\in X.

So, As the reflexive and transitive closure of R (that we will denote by \overline{R}) is in particular reflexive, we must add to R  the elements \{(1,1) , (2,2),(3,3),(4,4) \}

A transitive relation R is one in which if the pair (a,b) and the pair (b,c) are in there, then the pair (a,c) must be there too.

So, to complete the relation R to be reflexive and transitive we must add the pair (1,3) (because (1,2),(2,3) are in R), the pair (2,4), and the pair (1,4) because we added the pair (2,4).

Therfore we have that \overline{R}=\{(1,1),(2,2),(3,3),(4,4),(1,2)(2,3)(3,4),(1,3),(1,4)\}.

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