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3 years ago

What are the intercepts of the line?

Mathematics

1 answer:

Schach [20]3 years ago

3 0

To solve your X int you substitute 0 for y.

X int-
-5x+9(0)=-18
-5x=-18
X= 18/5 and the coordínate is (18/5,0)

Then to solve for y int you substitute 0 for x.

-5(0)+9y=-18
9y=-18
Y= -2 and the coordinate is (0,-2)

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Find the volume of the figure

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Step-by-step explanation:

Split it in 2.

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14*10*8 = 1120

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3 years ago

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3 years ago

Read 2 more answers

15 players for a softball team show up for a game: (a) How many ways are there to choose 10 players to take the field? 3003 (b)

prohojiy [21]

Answer:

(a) 3003 ways

(b) 10897286400 ways

Step-by-step explanation:

Given

$n = 15$ --- 15 players

Solving (a) Ways of selecting 10 players.

This implies combination.

So, we have:

$r=10$

Using:

$^nC_r = \frac{n!}{(n-r)!r!}$

We have:

$^{15}C_{10} = \frac{15!}{(15-10)!10!}$

$^{15}C_{10} = \frac{15!}{5!10!}$

Simplify

$^{15}C_{10} = \frac{15*14*13*12*11*10!}{5!10!}$

$^{15}C_{10} = \frac{15*14*13*12*11}{5!}$

$^{15}C_{10} = \frac{15*14*13*12*11}{5*4*3*2*1}$

$^{15}C_{10} = \frac{360360}{120}$

$^{15}C_{10} = 3003$

Solving (b) Ways of assigning positions to 10 players.

This implies permutation.

So, we have:

$r=10$

Using:

$^nP_r = \frac{n!}{(n-r)!}$

We have:

$^{15}P_{10} = \frac{15!}{(15-10)!}$

$^{15}P_{10} = \frac{15!}{5!}$

Solve each factorial

$^{15}P_{10} = \frac{1307674368000}{120}$

$^{15}P_{10} = 10897286400$

Solving (c) Ways of choosing at least 1 woman

We have:

$Men = 10$

$Women = 5$

Ways of selecting 10 players is: (a) 3003 ways

Since the number of men are 10, there is 1 way of selecting 10 men (i.e. selection without women)

Using complement rule:

At least 1 woman = Total - No woman

$At\ least\ 1\ woman = 3003 - 1$

$At\ least\ 1\ woman = 3002$

5 0

3 years ago