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3 years ago

What are the intercepts of the line?

Mathematics

1 answer:

Schach [20]3 years ago

3 0

To solve your X int you substitute 0 for y.

X int-
-5x+9(0)=-18
-5x=-18
X= 18/5 and the coordínate is (18/5,0)

Then to solve for y int you substitute 0 for x.

-5(0)+9y=-18
9y=-18
Y= -2 and the coordinate is (0,-2)

You might be interested in

Is (6,3) a solution to this system of equations y=3x - 3 3x - y =3

aleksandr82 [10.1K]

Answer:

It is not a solution

Step-by-step explanation:

Plug the point into the equations and check to see if they are true

y=3x - 3

3 = 3(6) -3

3 = 18-3

3 = 15

False

We do not need to check the other equation since this is false

3 0

3 years ago

Calculus Problem

Roman55 [17]

The two parabolas intersect for

$8-x^2 = x^2 \implies 2x^2 = 8 \implies x^2 = 4 \implies x=\pm2$

and so the base of each solid is the set

$B = \left\{(x,y) \,:\, -2\le x\le2 \text{ and } x^2 \le y \le 8-x^2\right\}$

The side length of each cross section that coincides with B is equal to the vertical distance between the two parabolas, $|x^2-(8-x^2)| = 2|x^2-4|$ . But since -2 ≤ x ≤ 2, this reduces to $2(x^2-4)$ .

a. Square cross sections will contribute a volume of

$\left(2(x^2-4)\right)^2 \, \Delta x = 4(x^2-4)^2 \, \Delta x$

where ∆x is the thickness of the section. Then the volume would be

$\displaystyle \int_{-2}^2 4(x^2-4)^2 \, dx = 8 \int_0^2 (x^2-4)^2 \, dx \\\\ = 8 \int_0^2 (x^4-8x^2+16) \, dx \\\\ = 8 \left(\frac{2^5}5 - \frac{8\times2^3}3 + 16\times2\right) = \boxed{\frac{2048}{15}}$

where we take advantage of symmetry in the first line.

b. For a semicircle, the side length we found earlier corresponds to diameter. Each semicircular cross section will contribute a volume of

$\dfrac\pi8 \left(2(x^2-4)\right)^2 \, \Delta x = \dfrac\pi2 (x^2-4)^2 \, \Delta x$

We end up with the same integral as before except for the leading constant:

$\displaystyle \int_{-2}^2 \frac\pi2 (x^2-4)^2 \, dx = \pi \int_0^2 (x^2-4)^2 \, dx$

Using the result of part (a), the volume is

$\displaystyle \frac\pi8 \times 8 \int_0^2 (x^2-4)^2 \, dx = \boxed{\frac{256\pi}{15}}}$

c. An equilateral triangle with side length s has area √3/4 s², hence the volume of a given section is

$\dfrac{\sqrt3}4 \left(2(x^2-4)\right)^2 \, \Delta x = \sqrt3 (x^2-4)^2 \, \Delta x$

and using the result of part (a) again, the volume is

$\displaystyle \int_{-2}^2 \sqrt 3(x^2-4)^2 \, dx = \frac{\sqrt3}4 \times 8 \int_0^2 (x^2-4)^2 \, dx = \boxed{\frac{512}{5\sqrt3}}$

7 0

2 years ago

Indicate a general rule for the nth term of this sequence. -6b, -3b, 0b, 3b, 6b. . .

GREYUIT [131]

Answer:

a(n) = -16b + (n - 1)(3b)

Step-by-step explanation:

First term is -6b.

Common difference is 3b; each new term is equal to the previous one, plus 3b.

Formula for this arithmetic sequence is

a(n) = -16b + (n - 1)(3b)

4 0

3 years ago

Will mark as brainliest if correct

Nataly_w [17]

Answer:

X = 2?

Step-by-step explanation:

Have a great day

6 0

3 years ago

How are the commutative property of addition and the commutive property of multiplication alike

andrew11 [14]

They both have an answer that is bigger than the numbers being added or multiplied together <span />

7 0

3 years ago